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irina [24]
3 years ago
9

Which statements about triangles are true? Select all that apply. Two triangles can be put together to form a parallelogram. The

area of a triangle can be found using the formula A = 2bh. All triangles have an area that is one half the area of a rectangle with the same base and height. A diagonal can split a rectangle with an area of 40 square units into two triangles with areas of 20 square units each. A triangle with a base and height of 4 units has a greater area than a square with the same dimensions.

Mathematics
2 answers:
klio [65]3 years ago
6 0

Answer:

The Answers Are Listed  Below!

Step-by-step explanation:

Tanya [424]3 years ago
5 0

Answer:

1 and 3 and 4

Step-by-step explanation:

  • Two triangles can be put together to form a parallelogram
  • All triangles have an area that is one half the area of a rectangle with the same base and height.
  • A diagonal can split a rectangle with an area of  40 square units into two triangles with areas of 20 square units
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Convert from rectangular to polar coordinates:Note: Choose r and θ such that r is non-negative and 0 ≤ θ < 2πa. (6,0)b. (9,9/
Anuta_ua [19.1K]

Answer:

The polar coordinates are as follow:

a. (6,2π)

b. (18, π/3)

c. (2√2 , 3π/4)

d. (2, 5π /6)

Step-by-step explanation:

To convert the rectangular coordinates into polar coordinates, we need to calculate r, θ .

To calculate r, we use Pythagorean theorem:

r = \sqrt{ x^{2} +y^{2} } ---- (1)

To calculate the θ, first we will find out the θ '  using the inverse of cosine as it is easy to calculate.

So,    θ '  = cos ⁻¹  (x/r)

If  y  ≥  0  then  θ  =  ∅

If  y  <  0  then  θ  =  2 π  −  ∅

For a. (6,0)

Sol:

Using the formula in equation (1). we get the value of r as:

r = \sqrt{6^{2} + 0^{2}  }

r = 6

And ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (6/6)

∅  =cos ⁻¹   (1) = 2π

As If  y  ≥  0  then  θ  =  ∅

So ∅ = 2π

The polar coordinates are (6,2π)

For a. (9,9/\sqrt{3})

Sol:

r = 9 + 3(3) = 18

and ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (9/18)

∅ = cos ⁻¹   (1/2) = π/3

As  If  y  ≥  0  then  θ  =  ∅

then θ  = π/3

The polar coordinates are (18, π/3)

For (-2,2)

Sol:

r =√( (-2)²+(2)² )

r = 2 √2

and ∅  = cos ⁻¹  (x/r)

∅ = cos ⁻¹  (-2/ 2 √2)

∅ = 3π/4

As  If  y  ≥  0  then  θ  =  ∅

then   θ  = 3π/4

The polar coordinates are (2√2 , 3π/4)

For (-√3, 1)

Sol:

r = √ ((-√3)² + 1²)

r = 2

and ∅  = cos ⁻¹  (x/r)

∅  = cos ⁻¹ ( -√3/2)

∅  = 5π /6

As  If  y  ≥  0  then  θ  =  ∅

So  θ  = 5π /6

The polar coordinates are (2, 5π /6)

6 0
3 years ago
Please help me, giving brainliest.
emmainna [20.7K]

I'm not sure what you want but the slope for each graph from left to right is 5, -7/8, -2.

The equation of each graph from left to right in slope intercept form is

y = 5x + 2, y = -7/8x - 11/8, y = -2x + 6.

4 0
4 years ago
Kenny has 576 baseball cards. He would like
Papessa [141]

Answer:

Divide 576 by 12 and you'll get your answer.

5 0
3 years ago
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Look at the rectangle and the square: Ada says that the length of diagonal SQ is two times the length of diagonal OM. Is Ada cor
Musya8 [376]

Answer:

No, she is wrong.

Step-by-step explanation:

A diagonal of square or rectangle is equals to hypotenuse of a triangle. So you can apply Pythagoras Theorem to solve it :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Rectangle,

{qs}^{2}  =  {rs}^{2}  +  {qr}^{2}

{qs}^{2}  =  {16}^{2}  +  {8}^{2}  = 320

qs =  \sqrt{320}  = 17.9 \: inches

Square,

{om}^{2}  =  {lo}^{2}  +  {lm}^{2}

{om}^{2}  =  {8}^{2}  +  {8}^{2}  = 128

om =  \sqrt{128}  = 11.3 \: inches

Given that QS is 17.9 and OM is 11.3. So SQ is not 2 times greater than OM.

17.9 \div 11.3 = 1.58 \: (not \: equals \: to \: 2)

7 0
3 years ago
Suppose you roll two number cubes. What is the probability of getting:
Usimov [2.4K]

Answer:

are a, b, and c the options or are they different questions?

8 0
2 years ago
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