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kiruha [24]
3 years ago
11

How do you factor using the grouping method

Mathematics
2 answers:
Olin [163]3 years ago
6 0
To factor<span> a trinomial in the form ax</span>2<span> + bx + c, find two integers, r and s, whose sum is b and whose product is ac. Rewrite the trinomial as ax</span>2<span> + rx + sx + c and then use </span>grouping<span> and the Distributive Property to </span>factor<span> the polynomial.</span>
Olegator [25]3 years ago
3 0
Essentially you need to find some common factor between two terms and then group them. It is slightly to conceptualize and understand. an ez method is <span>(a)(c) = n

so if i have ax + bx + c then i need to find the product of a and c (n)  and then find two numbers that are multiply to n and add to b
</span>
So EXAMPLE TIME:

2x² + 5x + 3

n = 6
3 x 2 = 6 and 3 + 2 = 5

2x^2 + 3x + 2x + 3

(2x^{2} + 2x) + (3x + 3)

2x(x+1) + 3(x+1)    Now we can group!

(2x+3)(x+1)



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Answer:

You asked to solve questions 3 and 5

<h3>#3</h3>

Since CD = EF,

  • 9x - 1 = 41 - 5x
  • 9x + 5x = 41 + 2
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  • x = 3
  • EF = 41 - 5*3
  • EF = 26
<h3>#5</h3>

MN = NP as their perpendicular bisectors are of same length.

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Help with cal 2 exercise involving integrals?
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\displaystyle\int\frac{\sqrt{x^2+1}}x\,\mathrm dx=\int\frac{\sqrt{\tan^2B+1}}{\tan B}\sec^2B\,\mathrm dB

\tan^2B+1=\sec^2B

\sqrt{\sec^2B}=\sec B (provided that \sec B>0)

Then

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