All categories

2 years ago

How do you factor using the grouping method

2 answers:

6 0

To factor a trinomial in the form ax2 + bx + c, find two integers, r and s, whose sum is b and whose product is ac. Rewrite the trinomial as ax2 + rx + sx + c and then use grouping and the Distributive Property to factor the polynomial.

Olegator [25]2 years ago

3 0

Essentially you need to find some common factor between two terms and then group them. It is slightly to conceptualize and understand. an ez method is (a)(c) = n

so if i have ax + bx + c then i need to find the product of a and c (n) and then find two numbers that are multiply to n and add to b

So EXAMPLE TIME:

2x² + 5x + 3

n = 6
3 x 2 = 6 and 3 + 2 = 5

2x^2 + 3x + 2x + 3

(2 $x^{2}$ + 2x) + (3x + 3)

2x(x+1) + 3(x+1) Now we can group!

(2x+3)(x+1)

You might be interested in

A new car that costs $17,500 loses 25 percent of its value in the first year. How much is the loss of the value.

EastWind [94]

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{25\% of 17500}}{\left( \cfrac{25}{100} \right)17500}\implies 4375$

4 0

3 years ago

Write a function to model the data.?

Wewaii [24]

Answer:

the seven question is not clear

6 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

Edmundo used a number line to show the solution for the inequality |2x-6|<4 Which number line shows the solution? HURRY PLEAS

Law Incorporation [45]

Break into 2 equatins to get x's:

2x-6<4 and 2x-6>-4

Solve for x in both:

2x-6<4
2x<10
x<5

2x-6>-4
2x>2
x>1

Graph both inequalities on the same number line:

<---0-----1-----2-----3-----4-----5-----6--->

6 0

3 years ago

Read 2 more answers

Which inequality represents all possible solutions of -6n<-12

inna [77]

The answer is n>2. ......

7 0

3 years ago