This is the worksheet I’m doing https://www.manhassetschools.org/cms/lib8/NY01913789/Centricity/Domain/710/Aim%2082%20Pd%209%20KEY.pdf
The slope between the points (x1,y1) and (x2,y2) is
slope=(y2-y1)/(x2-x1)
(0,6) and (5,-4)
x1=0
y1=6
x2=5
y2=-4
slope=(-4-6)/(5-0)=-10/5=-2
slope=-2
Answer:
Linear correlation exists
Step-by-step explanation:
Given the data :
X : | 2 4 5 6
Y : | 6 9 8 10
Using technology to fit the data and obtain the correlation Coefficient of the regression model,
The Correlation Coefficient, r is 0.886
To test if there exists a linear correlation :
Test statistic :
T = r / √(1 - r²) / (n - 2)
n = number of observations
T = 0.886 / √(1 - 0.886²) / (4 - 2)
T = 0.866 / 0.3535845
T = 2.449
Comparing Pvalue with α
If Pvalue < α ; Reject H0
Pvalue = 0.1143
α = 0.05
Pvalue > α ; We reject the null and conclude that linear correlation exists
Answer:
0.006
Step-by-step explanation:
