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ludmilkaskok [199]
3 years ago
11

A gas occupies 1.00 L at standard temperature. What is the volume at 333.0°C?

Chemistry
1 answer:
AURORKA [14]3 years ago
7 0
We use Charles's Law: V1/T1=V2/T2

Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K

Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L

Hope this would help :))

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Answer:

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Explanation:

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Which agents cause both chemical and physical weathering
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A Carnot cycle operates between the temperatures limits of 400 K and 1600 K, and produces 3600 kW of net power. The rate of entr
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The rate of entropy change:

The rate of entropy change of the working fluid during the heat addition process is 3 kW/K

What is the Carnot cycle?

  • The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession.
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The entropy of a system:

The rate of heat addition is expressed as,

Q = \frac{WT_{H}}{T_{H}- T_{L}}

The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,

S_{gen} = \frac{Q}{T_{H}} = \frac{W}{T_{H} - T_{L}}

Calculation:

<u>Given:</u>

T_{L} = 400K

T_{H} = 1600K

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Put all the values in the above equation, and we get,

S_{gen} = \frac{W}{T_{H} - T_{L}} = \frac{3600}{1600-400} = 3 kW/K

The rate of entropy change is 3 kW/K

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2 years ago
Two<br>moin tunetons of carbohydraus​
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Answer:

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Find the volume of a gas at standard pressure if its volume at 1.9 atm is 80 ml?
kogti [31]

Answer:

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Explanation:

Step 1: Given data

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  • Initial volume of the gas (V₁): 80 mL
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  • Final volume of the gas (V₂): ?

Step 2: Calculate the final volume of the gas

For an ideal gas, we can calculate the final volume of the gas using Boyle's law.

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Since the pressure decreased, the volume of the gas increased.

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