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ludmilkaskok [199]
3 years ago
11

A gas occupies 1.00 L at standard temperature. What is the volume at 333.0°C?

Chemistry
1 answer:
AURORKA [14]3 years ago
7 0
We use Charles's Law: V1/T1=V2/T2

Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K

Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L

Hope this would help :))

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