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ludmilkaskok [199]
3 years ago
11

A gas occupies 1.00 L at standard temperature. What is the volume at 333.0°C?

Chemistry
1 answer:
AURORKA [14]3 years ago
7 0
We use Charles's Law: V1/T1=V2/T2

Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K

Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L

Hope this would help :))

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Answer:

We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to  make 100 mL of a 0.2 M fruit drink solution.

Explanation:

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<em>(MV) before dilution = (MV) after dilution.</em>

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M after dilution = 0.2 M, V after dilution = 100 mL.

<em>∴ V before dilution = (MV) after dilution / M before dilution </em>= (0.2 M)(100 mL) / (1.0 M) = <em>20.0 mL.</em>

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8 0
3 years ago
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If you set up an experiment with two different independent variables, then the results would be_____.
MariettaO [177]

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When you set up an experiment, you must make sure that you control the variables such that only one independent variable changes at a time, while all the remainder conditions (the other independent variables) are controlled (fixed).

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Dafna11 [192]

Answer:

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Explanation:

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