<span>Answer: option (3) energy, charge and mass.
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<span>Explanation:
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<span>1) The conservation of energy is a universal principle: energy is neither created nor destroyed. This is the first law of thermodynamic.
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<span>2) Mass conservation is another universal principle: mass is neither created nor destroyed. This principle is the base of the stochiometry: thas mass of the reactans equal the mass of the products. Another consequence, since the atoms are not transformed in the chemical reactions, is that the number of each kind of atoms in the reactants equal the number of the same kind of atoms in the products.
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<span>3) The third principle is the conservation of charge. Also, charge is neither created nor destroyed. The electrons gained/lost by one species are lost/gained by other species. So, when one atom or molecule is oxidized other is reduced.</span>
Your answer is D, OH-! correct me if I’m wrong.
<h2>0.2 atm </h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is

Since we're finding the new pressure

We have

We have the final answer as
<h3>0.2 atm</h3>
Hope this helps you
Answer:
Please, see attached two figures:
- The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.
- The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.
Explanation:
The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>
From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.
Assuming density 1.0 g/mol for water, 10 mL of water is:
Thus, the solutibily is:

Answer:
0.266 moles of Na⁺
Explanation:
First step we dissociate the salt:
Na₃AsO₄ → 3Na⁺ + AsO₄⁻³
From 1 mol of sodium arsenate, we must have 3 moles of sodium cation and 1 mol of arsenate.
We determine the moles of salt:
18.4 g . 1 mol/ 207.89 g = 0.0885 moles of salt.
We apply the followring rule of three:
1 mol of salt has 3 moles of Na⁺
0.0885 moles of salt may have (0.0885 . 3) / 1 = 0.266 moles of Na⁺