Energy(heat) required to raise the temperature of water : 418.6 J
<h3>Further explanation </h3>
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Specific heat of water = 4.186 J/g*C.
∆T(raise the temperature) : 10° C
mass = 10 g
Heat required :

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Answer:
0.212
Explanation:
(5.30g) / (5.30g + 19.7g)
Answer:
2.30 × 10⁻⁶ M
Explanation:
Step 1: Given data
Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M
Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³
Step 2: Write the reaction for the solution of Mg(OH)₂
Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)
Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂
We will use the following expression.
Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²
[OH⁻] = 2.30 × 10⁻⁶ M
Answer:
2,3,6,1
2,3,6,1
Explanation:
The unbalanced reaction expression is given as:
AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.
aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃
Conserving Al; a = 2d
Br: 3a = c
K: 2b = c
S: b = 3d
O: 4b = 12d
Let a = 1, c = 3, d =
b =
Multiply through by 2 to give;
a = 2, b = 3, c = 6 and d = 1
2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃