For a perpendicular bisector
There are two rules.
1) It is perpendicular to the segment so it makes an angle of 90°
2) It divides the segment in two equal parts or it passes through the midpoint of the segment.
As RS is the perpendicular bisector of PQ.
So T is the midpoint
m<PTR = 90° is true
T is the midpoint of PQ is true.
RS is the perpendicular bisector of PQ is false
RS ⊥ PQ is true
RT = ST is false
PT = QT is true
A, B, D & F are true.
Answer:
Step-by-step explanation:
Substitution method:
y= -2x + 2
x - 2y = 6
so y = (-2x + 2)
Substitute into y
Hence x - 2y = 6 is:
x + 2x +2 = 6 (+2x because there was - in the equations so -×- = +)
3x + 2=6
Then bring 2 to the other side so
3x = 6-2
3x = 4
x = 3/4 or 0.75
To find y :
y= (-2 × 3/4) + 2
y = -1.5 +2
y = 0.5
That's all I can do for now!
There are 4! = 24 poosible permutations of the four letters. Let the letters be A, B, C and D. Two permutations will have only letter A in the correct envelope, two more permutations will have only letter B in the correct envelope, two more will have only letter C in the correct envelope and two more will have only letter D in the correct envelope. Therefore 8 out of the 24 possible permutations will have only one letter with the correct address. The required probability is 8/24 = 1/3.
Answer:
1. use a calculator to help
2. that's wrong because it equals 1.333...
Find the least common multiples of 4, 10, 12, 15
multiples of 4:
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80
multiples of 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120
multiples of 12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120
multiples of 15: 15, 30, 45, 60, 75, 90, 105, 120, 135, 150
The least common multiple of 4, 10, 12, and 15 is 60.
4 x 15 = 60
10 x 6 = 60
12 x 5 = 60
15 x 4 = 60
