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Vitek1552 [10]
3 years ago
5

What is 60/d when d=10

Mathematics
2 answers:
erastova [34]3 years ago
3 0
It is 6 60 divided by 10 is 6
timama [110]3 years ago
3 0
60/d
If d = 10 then put 10 in place of the d above
60/10

So 60 divided by 10... How many times does 60 go into 10?

Answer = 6
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20 POINTS<br> HELP ME PLEASE<br> How many solutions does the system have
finlep [7]

Answer:

Two

Step-by-step explanation:

x² + 4 = 4x + 1

x² - 4x + 3 = 0

x² - 3x - x + 3 = 0

x(x - 3) - (x - 3) = 0

(x - 3)(x - 1) = 0

x = 1, 3

y = 4(1) + 1 = 5

y = 4(3) + 1 = 13

Two solutions: (1,5) (3,13)

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3 years ago
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Sloan [31]

Answer:

7

Step-by-step explanation:

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3 years ago
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The price of an item has been reduced by 85% the original price was $95 what is the price of the item
Yanka [14]

Answer:

14.25

Step-by-step explanation:

95 x 0.85 = 80.75

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3 0
3 years ago
Verify that your point from Question 2 is a solution to 2x-y=-12x−y=−1 AND is also a solution to y=5x-5y=5x−5. What does it mean
Vera_Pavlovna [14]

Answer:

(a) Verified

(b) They are simultaneous equations

Step-by-step explanation:

Given

2x - y = -1

y =5x - 5

Required

Verify that: (x,y) = (2,5) is a solution

We have:

2x - y = -1

Substitute: (x,y) = (2,5)

2 * 2 - 5 = -1

Evaluate all products

4 - 5 = -1

Subtract:

-1 = -1

<em>Because both sides of the equation are equal, then the point is a solution</em>

<em></em>

Also: y =5x - 5

Substitute: (x,y) = (2,5)

5 = 5 * 2 - 5

Evaluate all products

5 = 10 - 5

Subtract:

5 = 5

<em>Because both sides of the equation are equal, then the point is a solution</em>

<em></em>

<em></em>

Because the given point is a solution to both equations, then they are simultaneous equation

7 0
3 years ago
1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may
SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}

Then, the sum of all of these must be 78, that is:

C+P+PC=78

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

47+P+15=78

Simplifying:

62+P=78

Now we solve for P by subtracting 62 on both sides:

\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}

Therefore, there are 16 students in physics

3 0
1 year ago
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