F(x)=22xplus 33 and g(x)=x2−44x−55, find (g◦f)(88)
1 answer:
F(x) = 22x + 33
g(x) = x² - 44x - 55
(g о f)(88) = (22(88) + 33)² - 44(22(88) + 33) - 55
(g о f)(88) = (1936 + 33)² - 44(1936 + 33) - 55
(g о f)(88) = (1969)² - 44(1969) - 55
(g о f)(88) = 3,876,961 - 86,636 - 55
(g о f)(88) = 2,790,325 - 55
(g о f)(88) = 3,790,270
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