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Fynjy0 [20]
2 years ago
8

5.9. 13.... Find the 31st term.

Mathematics
1 answer:
morpeh [17]2 years ago
4 0

Answer:

129

Step-by-step explanation:

None

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E = {10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23}
Nata [24]

Answer:

A=11,13,17,19 B=12,18 None=10,14,16,19 Both=15

Step-by-step explanation:

11,13,15,17,19 are all odd so they go in A

12,15,18 Are all multiples of 3 so they go in B

10,14,16,19 Are not classified so they go outside of the diagram but inside E

15 is odd and a multiple of 3 so put it in the center and not with A and B

6 0
3 years ago
A data value that is much higher or much lower then the other values on the data set?
Nitella [24]
A. Outlier is the answer.
5 0
3 years ago
Ryan drove for 4.5 hours to his uncle’s house. His uncle lives 234 miles away. Assuming Ryan drove at a constant rate, at what s
Fantom [35]
If you were to find the constant rate, you would have to take 4.5 and divide it into 234 to get the answer

You would get 52 as the constant speed

5 0
3 years ago
Read 2 more answers
Write the equation of the line PARALLEL to the line y = 4x - 9 that passes through the
german

Answer:

y = 4x + 12

Step-by-step explanation:

The slope of the line y = 4x - 9 is 4.

The slope of the line we are looking for is also 4.

y - y1 = m(x - x1)

y - 4 = 4[x - (-2)]

y - 4 = 4(x + 2)

y - 4 = 4x + 8

y = 4x + 12

Answer: y = 4x + 12

6 0
3 years ago
Read 2 more answers
The graph of a quadratic function has a vertex at the point (8,6). It passes through the point (-4,-5). Which of the following e
Mandarinka [93]

Answer:

y= -11/144(x-8)^2+6

Step-by-step explanation:

This equation can be represented in vertex form, which is:  

y=a(x-h)^2+k

If we plug in 8 as h and 6 as k we get the following equation:

y=a(x-8)^2+6

Now we have to plug in x and y. We can use the other point (-4,-5) and plug it into the equation and get:

-5=a(-4-8)^2+6

Once we solve this we get a= -11/144

Now we have to plug in -11/144 into the original equation to get

y = -11/144 (x-8)^2 + 6

6 0
3 years ago
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