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adoni [48]
3 years ago
7

According to the general equation for conditional probability, if p (a^b')=1/6 and p(b')=7/12 , what is the value of p(a[b)?

Biology
1 answer:
Alex3 years ago
5 0
P(B) = 1 - P(B') = 1 - (7/12) = 5/12 <span>P(A∩B)=<span><span>P(A∩<span>B′</span>)/</span><span>P(<span>B′</span>) </span></span>× <span><span>P(B)/</span>1

</span></span>Plugging values into the last equation we get: <span>P(A∩B)=<span><span>1×12×5 / </span><span>6×7×12 </span></span>= <span>542</span></span>
Now we can make use of the following formula <span>P(A|B)=<span><span>P(A∩B) / </span><span>P(B)</span></span></span><span> by plugging in the values that we have found.
</span>
<span>5/42 is the numerator and the denominator is 5/12.
</span>

The bottom (denominator) is P(B) which equals 5/12.

<span>P(A|B)=<span><span>5×12 / </span><span>42×5 = 6/210

6/210 = 2/7

</span></span></span><span>p(a[b]) = 2/7</span>

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