Explanation:
Carbon dioxide is a<u> product </u>of cellular respiration.
During respiration, the breakdown of glucose undergoes several steps in order to produce ATP, namely in glycolysis, the Kreb's cycle and oxidative phosphorylation.
overall: C6H12O6 (glucose) + 6 O2 → 6 CO2 + 6 H2O + ≈38 ATP
Further Explanation:
In all eukaryotic cells mitochondria are small cellular organelles bound by membranes, these make most of the chemical energy required for powering the biochemical reactions within the cell. This chemical energy is stored within the molecule ATP which is produced. Respiration in the mitochondria utilizes oxygen for the production of ATP in the Krebs’ or Citric acid cycle via the oxidization of pyruvate( through the process of glycolysis in the cytoplasm).
Oxidative phosphorylation describes a process in which the NADH and FADH2 made in previous steps of respiration process give up electrons in the electron transport chain these are converted it to their previous forms, NADH+ and FAD. Electrons continue to move down the chain the energy they release is used in pumping protons out of the matrix of the mitochondria.
This forms a gradient where there is a differential in the number of protons on either side of the membrane the protons flow or re-enter the matrix through the enzyme ATP synthase, which makes the energy storage molecules of ATP from the reduction of ADP. At the end of the electron transport, three molecules of oxygen accept electrons and protons to form molecules of water...
- Glycolysis: occurs in the cytoplasm 2 molecules of ATP are used to cleave glucose into 2 pyruvates, 4 ATP and 2 electron carrying NADH molecules. (2 ATP are utilized for a net ATP of 2)
- The Citric acid or Kreb's cycle: in the mitochondrial matrix- 6 molecules of CO2 are produced by combining oxygen and the carbon within pyruvate, 2 ATP oxygen molecules, 8 NADH and 2 FADH2.
- The electron transport chain, ETC: in the inner mitochondrial membrane, 34 ATP, electrons combine with H+ split from 10 NADH, 4 FADH2, renewing the number of electron acceptors and 3 oxygen; this forms 6 H2O, 10 NAD+, 4 FAD.
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Answer:
C
Explanation:
its c because it had cells that need them
Complete question:
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.
A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.
Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).
Answer:
The probability that the second child will also have the disease is 1/16.
Explanation:
<u>Available data:</u>
- Two genes independently inherited: one for blood type, the other for disease
- Man with type A blood x Woman with type B blood
- Both parents are heterozygous for the gene that causes the disease; Dd
If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.
Cross:
Parentals) AiDd x BiDd
Gametes) AD Ad iD id BD Bd iD id
Punnett square) AD Ad iD id
BD ABDD ABDd BiDD BiDd
Bd ABDd ABdd BiDd Bidd
iD AiDD AiDd iiDD iiDd
id AiDd Aidd iiDd iidd
F1) <u>Genotype</u>:
1/16 ABDD
2/16 ABDd
1/16 ABdd
1/16 AiDD
1/16 BiDD
2/16 AiDd
2/16 BiDd
1/16 Aidd
1/16 Bidd
1/16 iiDD
2/16 iiDd
1/16 iidd
<u>Phenotype:</u>
3/16 A/B normal
4/16 A normal
4/16 B normal
3/16 0 normal
1/16 0 affected by the disease.
During prophase, the parent cell chromosomes — which were duplicated during S phase — condense and become thousands of times more compact than they were during interphase. ... Cohesin forms rings that hold the sister chromatids together, whereas condensin forms rings that coil the chromosomes into highly compact forms.
