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Allushta [10]
3 years ago
12

Solve for x: 2|2x-2| +4=20

Mathematics
1 answer:
gregori [183]3 years ago
6 0
2|2x-2| +4=20\\
4|x-1|=16\\
|x-1|=4\\
x-1=4 \vee x-1=-4\\
x=5 \vee x=-3
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I WILL MARK BRAINLIEST!!
vagabundo [1.1K]

Answer:

4 days a week

Step-by-step explanation:

2+1=3

3+1/2+12=4

4 0
3 years ago
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You buy 1.75 pounds of apples and 2.05 pounds of oranges. Apples and oranges sell for the same price per pound. The total​ cost,
dlinn [17]

Answer:

1.75c+2.05c=4.18\\\\Per\ pound\ cost=c=\$1.1

Step-by-step explanation:

Cost\ of\ per\ pound\ apple=Cost\ of\ per\ pound\ oranger=c\\\\

Cost of Apples:

Amount\ of\ apples=1.75\ pounds\\\\Cost\ of\ apples=Amount\times per\ pound\ cost\\\\Cost\ of\ apples=1.75\times c\\\\Cost\ of\ apples=1.75c

Cost of oranges:

Amount\ of\ oranges=2.05\ pounds\\\\Cost\ of\ oranges=Amount\times per\ pound\ cost\\\\Cost\ of\ oranges=2.05\times c\\\\Cost\ of\ oranges=2.05c

Total cost:

Total\ cost\ of\ fruits=cost\ of\ apple+cost\ of\ oranges\\\\Total\ cost\ of\ fruits=1.75c+2.05c\\\\After\ coupon\ cost=\$ 3.43\\\\ Original\ cost=After\ coupon\ cost+coupon\ amount\\\\ Original\ cost=3.43+0.75=4.18

1.75c+2.05c=4.18\\\\3.8c=4.18\\\\c=\frac{4.18}{3.8}\\\\c=1.1\\\\Per\ pound\ cost\ of\ fruits=\$1.1

4 0
3 years ago
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

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3 years ago
I need help. Please
zubka84 [21]

Answer:

Answer is A.

Step-by-step explanation:

If you take the current cords of 'C' and add the cords it gives you: (4.5,-6.5). You end out with (3.5,-9,2). Hope this helps!

5 0
3 years ago
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A plane is a set of blank on a flat surface that extends forever
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Check the picture below.

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