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AveGali [126]
3 years ago
13

What is the equation of the graph????

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0
The graph shown above is a "parabola" and the parent function is x². So, we can start off at x². The graph of x² intersects the x and y-axis at (0, 0). In this case, it's simply being shifted up by 1 and intersects the x and y-axis at (0, 1). Therefore, the equation is:
y = x^2 + 1

To check, let's plug in 0 for x, and see what we get (we should get 1):
y = x^2 + 1
y = 0^2+1 = 0+1=1

We are right, so your final answer is x² + 1.
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10 POINTS IDENTIFY THE SLOPE, Y-INTERCEPT AND GRAPH.<br> 1. Y = 2x + 3<br> 2. Y = 3/4x - 2
Alenkasestr [34]

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3 years ago
Part A
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Answer:

Part A: There are 4 zeros of the polynomial function f(x)

Part B: The zeroes of the polynomial function f(x) are -4, -1, 0, 2 ⇒ C

Step-by-step explanation:

<em>The zeroes of a function are </em><em>the x-coordinates of the point of intersection between the graph of the function and the x-axis</em><em> (x-intercepts) which means </em><em>values of x at y = 0</em>

Part A:

In the given graph

∵ The graph of the function f(x) = -x^{4} - 3x³ + 6x² + 8x intersects the x-axis

   at 4 points

→ That means there are 4 values of x have y = 0

∴ The number of zeroes of the function is 4

∴ There are 4 zeros of the polynomial function f(x)

Part B:

∵ The graph intersects the x-axis at points (-4, 0), (-1, 0), (0, 0), (2, 0)

→ That means the values of x at y = 0 are -4, -1, 0, 2

∴ f(x) = 0 at x = -4, -1, 0, 2

∴ The zeroes of the polynomial function f(x) are -4, -1, 0, 2

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