4- 2/3 (4-1/6) divided by 3/4
parenthesis first
4 - 2/3 (3 5/6) divided by 3/4
change to an improper fraction (6*3+5)/6
4 - 2/3 ( 23/6)divided by 3/4
4 - 46/18 divide by3/4
copy dot flip
4 - 46/18 * 4/3
4 - 23/9 * 4/3
4 - 92/27
get a common denominator of 27
4*27/27 -92/27
108/27 - 92/27
16/27
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2
The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2
Answer:
x-6 <1
Step-by-step explanation:
Answer:
Except k=7, any real number for k would cause the system of equations to have no solution.
Step-by-step explanation:
In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.
Just for information, if k=7 the system will have infinitely many solutions.
