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3 years ago

what is the equation of the line, in slope-intercept form, that contains the points (−1, 2) and (2, −1)?

1 answer:

4 0

$The\ slope-intercept\ form:y=mx+b\\\\The\ slope-point\ form:y-y_1=m(x-x_1)\\\\The\ slope:m=\dfrac{y_2-y_1}{x_2-x_1}\\---------------------\\(-1;\ 2);\ (2;-1)\\\\m=\dfrac{-1-2}{2-(-1)}=\dfrac{-3}{3}=-1\\\\y-(-1)=-1(x-2)\\y+1=-x+2\ \ \ |subtract\ 1\ from\ both\ sides\\\boxed{y=-x+1}$

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PLEASE HELP ASAP! ITS URGENT! Thank you.

Arte-miy333 [17]

Let's plug in x = 2.

f(x) = x^2

f(2) = 2^2 ... replace every x with 2

f(2) = 4

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Now plug in x = 3.

f(x) = x^2

f(3) = 3^2 ... replace every x with 3

f(3) = 9

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And x = 5 as well.

f(x) = x^2

f(5) = 5^2 .... replace every x with 5

f(5) = 25

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We see that

f(2)+f(3) = 4+9 = 13

which is not equal to f(5) = 25.

So f(2)+f(3) = f(5) is false.

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Another way to phrase why it doesn't work is because (2,3,5) isn't a pythagorean triple. The equation 2^2+3^2 = 5^2 is false.

If it said f(3)+f(4) = f(5), then it would be correct because 3^2+4^2 = 5^2 is a true equation.

6 0

3 years ago

Please help me please

spayn [35]

Answer:

A. 34°

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] tanθ = opposite over adjacent
Inverse Trig

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = x

Opposite leg AC = 24

Adjacent leg CB = 35

Step 2: Solve for x

Substitute in variables [Tangent]: $\displaystyle tanx^\circ = \frac{24}{35}$
Inverse Trig [Tangent]: $\displaystyle x^\circ = tan^{-1}(\frac{24}{35})$
Evaluate: $\displaystyle x = 34.439^\circ$
Round: $\displaystyle x \approx 34^\circ$

4 0

3 years ago

Simplify (7x^2 + 3y-4)+(5x^2+5y)

Alex Ar [27]

\left[x _{2}\right] = \left[ \left( \frac{1}{6}\,i \right) \,\sqrt{3}\,\sqrt{\left( -4+8\,y\right) }\right][x2]=[(61i)√3√(−4+8y)] totally answer

5 0

3 years ago

Triangle PQR has vertices at the following coordinates : P(0,1) Q(3,2) R(5,-4) . Determine wether or not triangle PQR is a right

lord [1]

Here is my answer. Hope this help.

8 0

3 years ago

What is 2+1/10+3/ = 2

TiliK225 [7]

12-105-5 = -132 = -612 = -6.5 that is the answer i think check it but i think its right

4 0

3 years ago