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In-s [12.5K]
3 years ago
8

Quadrilateral RSTU is a parallelogram. What must be the value of x?

Mathematics
2 answers:
Luba_88 [7]3 years ago
7 0
I set x-3 and 3x-13 equal to each other and then got x equal to 5. So, I believe the correct answer would be C.) 5
Vlada [557]3 years ago
3 0

In this question, the  given quadrilateral is a parallelogram. And in a parallelogram, diagonals bisects each other. Therefore,

the parts of the diagonal with lengths

x-3  \ and \ 3x-13

have to be equal. That is

x-3=3x-13
\\
-3+13 = 3x-x
\\
10 =2x
\\
x =5

So out of the given options, correct option is the third option .


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Sphinxa [80]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Find three consecutive whose sum 237
Nina [5.8K]

Answer:

78 79 80

Step-by-step explanation:

Let the smallest number = x

Let the next number = x + 1

Let the largest number = x + 2

x + x + 1 + x + 2 = 237      Add together to get the equation

3x + 3 = 237                     Subtract 3 from both sides.

3x + 3 - 3 = 237 - 3          Combine the right

3x = 234                           Divide by 3

x = 234/3

x = 78

The smallest number is 78

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8 0
3 years ago
Read 2 more answers
Divide <br> (6-q+8q^3-4q^2)/(2q-2)
mestny [16]

Answer:


Step-by-step explanation:

        4q2 + 2q + 3                

 (2q - 2)  l  _  8q3  -  4q2  -  q  +  6                                        

                    8q3  -  8q2                      

                           _  4q2  -  q    

                               4q2 - 4q    

                                     _  3q  +  6  

                                        6q   +  6        

                                       -3q (remainder)  


  4q2 + 2q + 3 -3q / (2q - 2)      


hope this helps

4 0
3 years ago
The question is in the picture please help
ahrayia [7]

Answer:

Claim 2

Step-by-step explanation:

The Inscribed Angle Theorem* tells you ...

... ∠RPQ = 1/2·∠ROQ

The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.

... 2·∠RPQ = ∠ROQ

The symmetric property of equality says you can rearrange this to ...

... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ

_____

* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.

You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.

4 0
3 years ago
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jek_recluse [69]
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-i know its a little confusing its the best i could come up with

4 0
3 years ago
Read 2 more answers
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