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3 years ago

Help explain!!!! please

Mathematics

1 answer:

sammy [17]3 years ago

6 0

Bring the shape on the other side of the y axis. A mirror image.
It will be on the top right. That is quadrant 1

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A zoo has 2 male lions one sixth oh the lions are male lions how many lions are there at the zoo ?

Deffense [45]

I'm guessing there are 12 lions since half of twelve is 6 and there is only 2 male lions. I would put down 12. Hope that helps!

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4 years ago

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Find the length of each arc. Round your answers to the nearest tenth.

suter [353]

brainly.com/question/18907766

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3 years ago

A cone and a sphere both have a radius of 1. If you fill the cone with liquid, and pour it into the sphere, it fits exactly. Wha

PtichkaEL [24]

Answer and Step-by-step explanation:

First, solve for the volume of the sphere, then solve for the height of the cone using the volume of the sphere (which is said to be equal to the volume of the cone) and the radius given.

Volume formula of Sphere

V = $\frac{4}{3} \pi r^2$

Substitute 1 in for r

$\frac{4}{3} \pi (1)^2 = \frac{4}{3} \pi = 4.189$ = Volume

Finding the Height of a Cone

Volume formula for Cone: $V = \pi r^2\frac{h}{3}$

Solve for h

Multiply both sides by 3, then divide by pi and r^2.

$h = \frac{3V}{\pi r^2}$

Plug in the volume and the radius.

$h = \frac{3(4.189)}{\pi (1)^2}$

Simplify

$h = \frac{12.567}{\pi }$

h ≈ 4

4 is approximately the height.

#TeamTrees #PAW (Plant And Water)

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3 years ago

What is the y value when x equals 21? y=310-25(x)

Sati [7]

Answer:

Step-by-step explanation:

You subtract 310 from 25 and get 285 then you multiply 285 x 21 and I believe that should solve this equation.

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3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

4 years ago