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3 years ago

Help explain!!!! please

Mathematics

1 answer:

sammy [17]3 years ago

6 0

Bring the shape on the other side of the y axis. A mirror image.
It will be on the top right. That is quadrant 1

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Acar can travel 25 miles per gallon. Approximately how many gallons of fuel will the car need to travel 30

FrozenT [24]

Answer:

The gallons of fuel car need to travel 30 km is 0.75 approximately .

Step-by-step explanation:

Given:

The car can travel 25 miles per gallon. (1 mile = 1.6 km)

Now, we need to convert 25 miles into km .

25 miles = 25 × 1.6 km

= 40 km

So, the car can travel 40 km per gallon.

Then, we find out in 1 km how many gallons are used:

$40 km = 1 gallons$

$1\ km = \frac{1}{40}\ gallons$

$1\ km = 0.025\ gallons$

Now, we find out how much gallons of fuel will the car need to travel 30 km:

Gallons of fuel the car need to travel 30 km = $30\times 0.025$

= $0.75 gallons$ .

Therefore, the gallons of fuel car need to travel 30 km is 0.75 approximately.

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3 years ago

1. when y=7 , what is the value of x? 2. what is the y-intercept of the graph?

Yakvenalex [24]

1) Correct.

2) The y-intercept is when x=0, so it is (0,5).

7 0

2 years ago

The number 15, 56 rounded to the nearest thousand is 15,000. Which numbers could be the missing digit?

Virty [35]

The numbers 0, 1, 2, 3, 4 could all be the missing digit because they're all numbers that round down. hope this helped!

4 0

4 years ago

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Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

3 years ago

WILL GIVE BRAINLIEST! Translate into a variable expression. the sum of sixteen and c

Art [367]

Answer:

16+c

Step-by-step explanation:

Sum means we will have to add. When it says "sum of sixteen and c" it is telling us to add both sixteen and c together.

4 0

3 years ago

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