R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
The greatest area he can fence is 64 ft².
In order to maximize area and minimize perimeter, we use dimensions that are as close to equivalent as possible. 32 feet of fence for 4 sides gives us 8 feet of fence per side. We would have a square whose side length is 8; the area would be 8*8 = 64.
Answer:
(a)10 Outcomes
(b)
Step-by-step explanation:
An urn contains two blue balls (denoted
) and three white balls (denoted
).
In the selection, a ball is picked and replaced.
The possible outcomes of the experiment are:

(a)If the first ball drawn is blue. the outcomes are:

There are 10 outcomes if the first ball drawn is blue.
Probability that the first ball drawn is blue
