What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6y?
1 answer:
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Step-by-step explanation:
2x - 5 = y - 5
2x = y
x = y/2
y - 3 = x + 1
Substitute the value of x here,
y - 3 =
y - 3 =
2y - 6 = y + 2
y = 8
Now, x = 8/2
x = 4
So, go for D part, it is the correct answer.
Good Night/Day !