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3 years ago

Whats ski mask first ever song

Mathematics

2 answers:

Lelu [443]3 years ago

8 0

Answer:

it was catch me on soundclouud

Step-by-step explanation:

Margarita [4]3 years ago

5 0

01 all I see is money is ski masks first ever song

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A line passes through point (3, 7) and has a slope of 34. the equation of the line is A. y= 3/4x +19/4 or B. y=3x - 19 If point

uysha [10]

Y = mx + b
slope(m) = 3/4
(3,7)...x = 3 and y = 7
now we sub and find b, the y int
7 = 3/4(3) + b
7 = 9/4 + b
7 - 9/4 = b
28/4 - 9/4 = b
19/4 = b

so ur equation is : y = 3/4x + 19/4

if point A (x,5) lies on the line.....
y = 3/4x + 19/4......when y = 5
5 = 3/4x + 19/4
5 - 19/4 = 3/4x
20/4 - 19/4 = 3/4x
1/4 = 3/4x
(1/4) / (3/4) = x
1/4 * 4/3 = x
4/12 reduces to 1/3 = x......so point A is (1/3,5)...with x being 1/3

4 0

4 years ago

Can somebody help teach me how to solve quadratic equations? I have no idea what to plug in. Here are some examples of what I ne

guapka [62]

The best method that will work for any quadratic equation is to use the quadratic formula: x = (-b±√(b² - 4ac))/2a, this will work for any quadratic of the form ax² + bx + c = 0.

As for the last equation in the attachment, that is a cubic equation, these are much trickier to solve and as such the formula is much longer and very complicated. Therefore it is easier to see if it can be broken down into a linear term and a quadratic. This can be done by substituting integer values of x into the equation to see if it holds true. If both sides of the equation are equal for a given value of x then the equation ax³ + bx² + cx + d can be rewritten as (Ax + B)(px² + qx + r). This can then be put into the quadratic formula mentioned above.

4 0

3 years ago

Multiply 15×2.23 plz and ty

Arlecino [84]

Answer:

33.45

Step-by-step explanation:

Just multiply

Just put it like normally, forget the decimal for now, you don’t have to line it up due to it not being addition Or subtraction

You’ll get 3345 without the decimal

now there are 2 decimal places from 0 so

just move the decimal place 2 times to the left

33.45

4 0

3 years ago

Read 2 more answers

Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *

Luda [366]

Answer:

The answer to your question is $\frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1$

Step-by-step explanation:

Data

Foci (-2, 2) (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

2c = 6

c = 6/2

c = 3

3.- Determine a

2a = 10

a = 10/2

a = 5

4.- Determine b using the Pythagorean theorem

a² = b² + c²

-Solve for b

b² = a² - c²

b² = 5² - 3²

b² = 25 - 9

b² = 16

b = 4

5.- Find the center (1, 2) From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

$\frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1$

$\frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1$

3 0

3 years ago

Find LCM of: x2 - 9, 3x3 + 81

VikaD [51]

Answer:

$\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}$

Step-by-step explanation:

Given two expressions ,

$\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81$

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :- 

$= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]$

Factorising 3x³ + 81 

$= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }$

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

8 0

3 years ago

Whats ski mask first ever song​

Whats ski mask first ever song