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mash [69]
2 years ago
15

There were 15 students who brought an item for show-and-tell. Each student had 3 minutes to present their item. Write an equatio

n to find how long show-and-tell lasted. 15 × 3 = m 3 − 15 = m 15 ÷ m = 3 m × 3 = 15 m × 15 = 3
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
8 0

Answer:

m=15\times 3

Step-by-step explanation:

Total number of students = 15

Time given to each student to present their item= 3 minutes

So, total time for the show can be calculated as m=15\times 3 minutes

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The graph is shown for the equation y = –x + 4.
ivann1987 [24]

Answer:

Option C. y=-\frac{1}{2}(2x-8)

Step-by-step explanation:

we know that

If a system of two linear equations has an infinite number of solutions, then both equations must be identical

The given equation is

y=-x+4

<u><em>Verify each case</em></u>

Option A. we have

y=-4(x+1)

apply distributive property

y=-4x-4

Compare with the given equation

-x+4 \neq -4x-4

Option B. we have

y=-(x+4)

remove the parenthesis

y=-x-4

Compare with the given equation

-x+4 \neq -x-4

Option C. we have

y=-\frac{1}{2}(2x-8)

apply distributive property

y=-x+4

Compare with the given equation

-x+4=-x+4

therefore

This equation with the given equation form a system that has an infinite number of solutions

Option D. we have

y=x+4

Compare with the given equation

-x+4 \neq x+4

7 0
3 years ago
Use the discriminant to find the number of real solutions of the equation 3x^2 – 5x + 4 = 0
Virty [35]
To use the discriminant, first identify a, b, and c. In your equation a= 3 b = -5 and c = 4. Now plug into the discriminant b^2 - 4ac. Substituting yields (-5)^2 - 4(3)(4). Simplifying, 25 - 48 = -23. Since the discriminant has a negative value, there is no real solution to this equation.
4 0
2 years ago
Read 2 more answers
What is a true statement about negative exponents?
Nadya [2.5K]

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what x^{-2} is.

To find it, you would take the reciprocal of the x amount. So x^{-2} becomes \frac{1}{x^{2}}.

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So a^{3} would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase a^{3} to a^{5}, you would have to multiply a with a^{3} two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease a^{5} to a^{2}, you would have to divide a^{5} by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: \frac{1}{a^{3}} means that you are dividing 1 by a 3 times.

Hope this helps.

3 0
2 years ago
Which points are on the graph .... HELP ASAP
Dmitrij [34]

Answer:

I want to say its (-1,5) but I'm not sure

8 0
3 years ago
1.5(x +4) - 3 = 4.5 (x - 2)
Pavel [41]

Answer:

Step-by-step explanation:

x-4

7 0
2 years ago
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