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mash [69]
3 years ago
15

There were 15 students who brought an item for show-and-tell. Each student had 3 minutes to present their item. Write an equatio

n to find how long show-and-tell lasted. 15 × 3 = m 3 − 15 = m 15 ÷ m = 3 m × 3 = 15 m × 15 = 3
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer:

m=15\times 3

Step-by-step explanation:

Total number of students = 15

Time given to each student to present their item= 3 minutes

So, total time for the show can be calculated as m=15\times 3 minutes

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Artyom0805 [142]
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3 years ago
Can i get a list of prime numbers
bija089 [108]

well prime numbers are noting but whole number greater than 1 whose only factors are 1 and itself.

soo....the first few prime numbers are :

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149 etc.

and if u c .... all the numbers dont come in any other table rather that one and itself


5 0
3 years ago
I need help with this question!
ElenaW [278]

Answer:

True

Step-by-step explanation:

(x,y) becomes (-x,-y)

7 0
3 years ago
Can someone help? I’m almost done with this class.
melisa1 [442]

Answer:

750

300

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Step-by-step explanation:

4 0
3 years ago
The amount of soda in a 16-ounce can is normally distributed with a mean of 16 ounces and a standard deviation of .5 ounce. What
Firdavs [7]

Answer:

Probability that a randomly selected can will have less than 15.5 ounces is 0.1587.

Step-by-step explanation:

We are given that the amount of soda in a 16-ounce can is normally distributed with a mean of 16 ounces and a standard deviation of 0.5 ounce.

<em>Let X = amount of soda</em>

So, X ~ N(\mu=16,\sigma^{2} =0.5^{2})

The z-score probability distribution for normal distribution is given by;

               Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean amount = 16 ounces

            \sigma = standard deviation = 0.5 ounce

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a randomly selected can will have less than 15.5 ounces is given by = P(X < 15.5 ounces)

  P(X < 15.5 ounces) = P( \frac{  X -\mu}{\sigma} < \frac{ 15.5-16}{0.5} ) = P(Z < -1) = 1 - P(Z \leq 1)

                                                                 = 1 - 0.8413 = 0.1587

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.</em>

Hence, the probability that a randomly selected can will have less than 15.5 ounces is 0.1587.

3 0
4 years ago
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