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snow_tiger [21]

3 years ago

7

L

1 answer:

Harlamova29_29 [7]3 years ago

5 0

Answer:

(Z + 2•)

Step-by-step explanation:

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What is 8.1 divided by ( -0.9 ) ?

Ksju [112]

-9 hopefully this helps

8 0

3 years ago

Read 2 more answers

Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin

Anastasy [175]

Suppose $y_2(x)=y_1(x)v(x)$ is another solution. Then

$\begin{cases}y_2=vx^3\\{y_2}'=v'x^3+3vx^2//{y_2}''=v''x^3+6v'x^2+6vx\end{cases}$

Substituting these derivatives into the ODE gives

$x^2(v''x^3+6v'x^2+6vx)-x(v'x^3+3vx^2)-3vx^3=0$

$x^5v''+5x^4v'=0$

Let $u(x)=v'(x)$ , so that

$\begin{cases}u=v'\\u'=v''\end{cases}$

Then the ODE becomes

$x^5u'+5x^4u=0$

and we can condense the left hand side as a derivative of a product,

$\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0$

Integrate both sides with respect to $x$ :

$\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C$

$x^5u=C\implies u=Cx^{-5}$

Solve for $v$ :

$v'=Cx^{-5}\implies v=-\dfrac{C_1}4x^{-4}+C_2$

Solve for $y_2$ :

$\dfrac{y_2}{x^3}=-\dfrac{C_1}4x^{-4}+C_2\implies y_2=C_2x^3-\dfrac{C_1}{4x}$

So another linearly independent solution is $y_2=\dfrac1x$ .

3 0

3 years ago

I need the answer for this question

garri49 [273]

Answer:

The last pair are vertical.

Step-by-step explanation:

7 0

3 years ago

Evaluate the definite integral

Georgia [21]

$\displaystyle\int_{x=9}^{x=10}x\sqrt{x-9}\,\mathrm dx$

Let $y=x-9$ , so that $x=y+9$ and $\mathrm dx=\mathrm dy$ . The integral is then equivalent to

$\displaystyle\int_{y=0}^{y=1}(y+9)\sqrt y\,\mathrm dy=\int_0^1(y^{3/2}+9y^{1/2})\,\mathrm dy=\dfrac{32}5$

7 0

3 years ago

Solve for x*<br> (17x - 8)

djyliett [7]

Answer:x=4

Step-by-step explanation:

This triangle is an equilateral triangle with all angles equal.

Sum of angles in a triangle=180

17x-8+17x-8+17x-8=180

Collect like terms

17x+17x+17x-8-8-8=180

51x-24=180

51x=180+24

51x=204

Divide both sides by 51

51x/51=204/51

x=4

3 0

3 years ago