Answer: The limiting reactants for the reaction is, Mg
Explanation : Given,
Mass of = 10.1 g
Mass of = 10.5 g
Molar mass of = 24 g/mol
Molar mass of = 32 g/mol
First we have to calculate the moles of and .
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.421 moles of react with moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Hence, the limiting reactants for the reaction is, Mg