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choli [55]
3 years ago
13

Q: If the average speed of a species of tortoise is 0.36 km/h, what is that speed in cm/s?

Chemistry
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

36000 centimeters

Explanation:

If the average speed of a species of tortoise is 0.36 km/h, then it would be 36000 centimeters.

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What is the answer for this question
cestrela7 [59]

Answer:

The answer to your question is the second choice

Explanation:

Formula to calculate the heat of any substance

             Q cal= mCcal ΔTcal

Formula to calculate the heat of a metal. The heat will be negative because it releases heat.

                  Qm = -mCmΔTm

Now equal both formula

                   Qcal = Q m

           mCcalΔTm = -mCmetΔTmet

-Solve for Cmet

                 Cmet = -[mCcalΔTm] / mΔTmet

6 0
3 years ago
What is the different types of technology used for cloning animals?
gayaneshka [121]
There are three types of artificial cloning:
Gene cloning: copies a few segments of DNA or genes.
Reproductive cloning: it copies the whole animal.
Therapeutic cloning: produces embryonic stem cells for experiments aimed at creating tissues to replace injured or diseased tissues.
6 0
4 years ago
A gas has a volume of 300 mL in a rigid container at 50oC and 1.75 atm. What will be its pressure at 100K?
eduard

Answer:

Its pressure will be 0.54 atm at 100 K.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as the quotient between pressure and temperature equal to a constant:

\frac{P}{T} =k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 1.75 atm
  • T1= 50 °C= 323 K (being 0 C=273 K)
  • P2= ?
  • T2= 100 K

Replacing:

\frac{1.75 atm}{323 K} =\frac{P2}{100 K}

Solving:

P2= 100 k*\frac{1.75 atm}{323 K}

P2= 0.54 atm

<u><em>Its pressure will be 0.54 atm at 100 K.</em></u>

8 0
3 years ago
Give me a time table of how to revise my exam syllabus within 1 month
musickatia [10]

Explanation:

during the daytime just complete your lessons of biology, during the midday timechemistry or study it in evening, at night physics and just try to complete those chapters that are difficult for you and the easier one you could do at last simple and take Sunday as a day for revision...

Give 2hrs, 1hr each chapter...

4 0
3 years ago
2.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 12
Art [367]

Answer:

                      Molecular Formula  =  C₁₀H₈

Explanation:

Step 1: <u>Calculating Moles for each Element:</u>

C  =  Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)

C  =  8.60 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)

C =  0.1954 mol

H  =  Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)

H  = 1.41 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)

H =  0.1557 mol

Step 2: <u>Calculate the Smallest whole number ratio as,</u>

                                 C                                                        H

                              0.1954                                               0.1557

                      0.1954/0.1557                                  0.1557/0.1557

                               1.25                                                       1

Multiply ratio by 4,

                                 5                                                         4

Result:

          Empirical Formula of Propane is C₅H₄

Step 3: <u>Calculate Molecular Formula:</u>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  128.0 g.mol⁻¹

Empirical Formula Weight  =  5 (C) + 4 (H) =  64 g.mol⁻¹

So,

                     n  =  128.0 g.mol⁻¹ ÷ 64 g.mol⁻¹

                     n  =  2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × C₅H₄

                    Molecular Formula  =  C₁₀H₈

4 0
3 years ago
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