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Olenka [21]
3 years ago
9

What is the reciprocal of the negation of the reciprocal of the negation of $5$?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

-5%

Step-by-step explanation

you just have to flip it if it is positive you are turning to negative and if it is negativity you turn positive

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Given a point translated from A(1,2) to B(4,4). If a point C at (0,0) is translated in the same way, what will be its new endpoi
avanturin [10]

Answer:

B. (3,2)

Step-by-step explanation:

Step 1) When shifting from A(1,2) to B(4,4), the point shifted 3 units to the right (which means x=3) and 2 units upwards (which means y=2).

Step 2) So when you apply the same movements to point C(0,0), the new point will be (3,2).

See the diagram below. Step 1 is the graph on the left. Step 2 is the graph on the right. The movement is colored in green. Hope this helps!

7 0
2 years ago
Aaron answered 7 out of 12 questions correctly on his last English quiz. Find his grade
givi [52]
Divide 7 by 12
which would give you 0.58
so that’s 58%
7 0
2 years ago
Read 2 more answers
All questions are about this system of equations:
sertanlavr [38]
If we are eliminating x, we would multiply the 2nd equation by -5

5x + 18y = 23
x + 3y = 2....multiply by -5
-----------------
5x + 18y = 23
-5x - 15y = - 10 (result of multiplying by -5)
----------------add
0 + 3y = 13.....bye-bye x :)

6 0
3 years ago
List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct
zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

\sqrt{\dfrac{\left (n-1  \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1  \right )s^{2}}{\chi _{\alpha /2}^{}}}

s = \sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }

Where:

\bar x = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

\bar x = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = \sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} } = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }

\sqrt{\dfrac{\left (7-1  \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1  \right )2.854^{2}}{0.872}}

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

7 0
3 years ago
Simplify the expression <br> 9y+4-6y
Mashutka [201]

Answer:

3y+4

Step-by-step explanation:

9y-6y=3y

3 0
2 years ago
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