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Rama09 [41]
3 years ago
10

A number greater than 1000 whose prime factorization contains one prime number that does not repeat one prime number that repeat

s three times and one prime number that repeats twice
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0
Consider the prime factorization of 1000:

1000=10\cdot 10\cdot10=(2\cdot5)\cdot(2\cdot5)\cdot(2\cdot5)=2^3\cdot5^3

We see that the prime factorization of 1000 contains 5 repeating three times and 2 repeating three times.

We can keep 5 repeating 3 times, 

We can write a prime whose square is larger than 2^3, for example: 7^2

Then we can write any prime which does not repeat, for example 2.


Thus the number we formed is 2 \cdot7^2\cdot5^3=12,250


Answer: 12,250
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Answer:

Step-by-step explanation:

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If the population is decreasing 3% per year, it is decreasing 100% - 3% = 97% which, as a decimal, is .97. Our exponential function, then, is

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3 years ago
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3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

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Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

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x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
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