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Rama09 [41]
3 years ago
10

A number greater than 1000 whose prime factorization contains one prime number that does not repeat one prime number that repeat

s three times and one prime number that repeats twice
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
6 0
Consider the prime factorization of 1000:

1000=10\cdot 10\cdot10=(2\cdot5)\cdot(2\cdot5)\cdot(2\cdot5)=2^3\cdot5^3

We see that the prime factorization of 1000 contains 5 repeating three times and 2 repeating three times.

We can keep 5 repeating 3 times, 

We can write a prime whose square is larger than 2^3, for example: 7^2

Then we can write any prime which does not repeat, for example 2.


Thus the number we formed is 2 \cdot7^2\cdot5^3=12,250


Answer: 12,250
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Answer:

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Step-by-step explanation:

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One way (the mathematically correct way) is using the formula:

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Hope it helps :) and let me know if you want me to elaborate, or if the notation used was intended to be something else, as the subfactorial of 72 seems like an unnecessary amount of tedium.

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