Answer:
Step-by-step explanation:
Answer:
10635
Step-by-step explanation:
Honestly, I dunno. I just added it.
If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
ED = x - 5 <em>given</em>
DG = 4x - 38 <em>given</em>
ED = DG <em>definition of midpoint</em>
x - 5 = 4x - 38 <em>substitution</em>
-5 = 3x - 38 <em>subtraction property of equality (subtracted x from both sides)</em>
33 = 3x <em>addition property of equality (added 38 to both sides)</em>
11 = x <em>division property of equality (divided 3 from both sides)</em>
ED = x - 5 → ED = 11 - 5 → ED = 6 <em>substitution</em>
since ED = DG, then DG = 6 <em>transitive property</em>
ED + DG = EG <em>segment addition property</em>
6 + 6 = EG <em>substitution</em>
12 = EG <em>simplified like terms</em>
Answer: 12
The <em><u>correct answer</u></em> is:
At least 7 times.
Explanation:
Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.
After two times, we would have 0.9(0.9) = 0.81 = 81% of the water; each time she pours, the number of times 0.9 is multiplied by itself changes. This makes this an exponential inequality (it is not an equation, as we want "less than half of the water"):
To solve this, we will use logarithms:
