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alina1380 [7]
3 years ago
11

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t

han the width, x, which interval can be the possible widths?
Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

0 ft < w ≤ 7 ft

Step-by-step explanation:

A=wl,  where w, l >0

A≤175 ft²

l= w+18

w(w+18)≤175

w²+18w-175≤0

zeros of are -25 and 7

(w + 25)*(w - 7) ≤ 0

w+25≤0, w-7≥0 ⇒ w ⊂ ∅

w+25≥0, w-7≤0 ⇒ -25 ≤ w ≤ 7,

as w>0, we have answer: 0 < w ≤ 7

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