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alina1380 [7]
3 years ago
11

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t

han the width, x, which interval can be the possible widths?
Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

0 ft < w ≤ 7 ft

Step-by-step explanation:

A=wl,  where w, l >0

A≤175 ft²

l= w+18

w(w+18)≤175

w²+18w-175≤0

zeros of are -25 and 7

(w + 25)*(w - 7) ≤ 0

w+25≤0, w-7≥0 ⇒ w ⊂ ∅

w+25≥0, w-7≤0 ⇒ -25 ≤ w ≤ 7,

as w>0, we have answer: 0 < w ≤ 7

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2 years ago
Please help! Could you answer all!?
Brums [2.3K]

Answer:

1.) 48

2.) 65

3.) 36

Step-by-step explanation:

1.)     If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.

2.)     This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.

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3 0
3 years ago
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Answer:D

Step-by-step explanation:

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2 years ago
Will mark as brainliest! 40 points! Thanks!
n200080 [17]

When given a system of equations, the "solutions" are defined where two equations intersect, or meet.


A. The point where the lines p(x) and g(x) meet is (3, -1), and thus this is considered the solution set.

B. Because there are three lines in total, g(x) is able to intersect both lines one time, and so it has two pairs of solutions.

The first is (3, -1), which has already been established with p(x).

The second is (0, 5), and this is where it intersects with f(x).

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Hope my answer helped!

6 0
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