Answer:
huhh um whata re y trying to say?
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the set notations A = {a} B = {b, c} C = {a, b, d}
BUC = {a, b, c, d}
B∩C = {b}
a) A × (BUC) = {aa, ab, ac, ad}
b) A × (B ∩ C) = {ab}
c) (A × B) ∪ (A × C)
A × B = {ab, ac} and A × C = {aa, ab, ad}
(A × B) ∪ (A × C) = {aa, ab, ac, ad}
d) For (A × B) ∩ (A × C)
(A × B) ∩ (A × C) = {ab}
Note that the union (U) of two sets is the combination of all the elements in both sets while the intersection (∩)of two sets is the common elements that are found in both sets.
The Cartesian product of two sets is derived by mapping each of the element in the first set with all the element in the other set. It is denoted by the multiplication sign.
Answer:
Step-by-step explanation:
4.2x+4.7=18.6
Multiple each term by 10
42x + 47 = 186
Collecting like terms
42x = 186 - 47
42x = 139
x = 139/42
x = 3 13/42 or 3.3
X = first child
x +2 = 2nd child
x+ 4 = 3rd child
It doesn't matter if the ages are odd or even - there is two years between each child in age.
The sum would be
x + x + 2 + x + 4 or 3x + 6.
Lets try it with a sample age. Let's say the youngest is 5 middle is 7 and oldest is 9
The sum of their ages is 21 (5 + 7 + 9)
Using our answer of 3x + 6 where x is the age of the youngest child, we get
3(5) +6 which is also 21.
This could also be solved by having x represent the middle age child
x-2 is the youngest (2 years less than the middle)
x = the middle
x+2 is the oldest (2 years older than the middle)
The sum of these would be x-2 + x + x +2 or simply 3x (the 2's cancel out)
Since the middle child is 7 3x would mean 3 (7)=21
You could also set this up using x for the oldest child
x= oldest
x-2= middle
x-4= youngest (The sum of this is 3x - 6)
3 (9) -6 is also 21.