The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x
The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1
<h3>How to determine the quotient</h3>
The quotient expression is given as:
6x^3+2x^2−x divide by x
The above means that,
We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.
So, we have:
6x^3+2x^2−x divide by x = 6x^2 + 2x - 1
Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1
Read more about quotient at:
brainly.com/question/7068223
Answer:
y = -6/5x - 5
Step-by-step explanation:
Use rise over run to find the slope of the line, and the -5 comes from the y-intercept
Answer:
75 students out of 120
Step-by-step explanation:
75/120
W=166 degrees
okay so the total measure of the angles should be 360 so you gotta do 86+86+72+w=360
86+86+72=244
360-244=116