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KiRa [710]
3 years ago
14

What is the particles instantaneous speed at t=16 sec

Physics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

It's  3.6 meters per second less than my speed was
at 4:19 PM last Tuesday.

Does that tell you anything ?
Why not ?

 
You might be interested in
How much heat is absorbed by a 28g iron skillet when its temperature rises from 7oC to 29oC?
prohojiy [21]
From the information given above, 
Mass [M] = 28 g
Change in temperature = 29 - 7 = 22 
Specific heat of iron = 0.449 [This value is constant]
The formula for calculating heat absorbed, Q is
Q = Mass * Specific heat of Iron * change in temperature
Q = 28 * 0.449 * 22 = 276.58 J<span />
5 0
3 years ago
Calculate the maximum capillary rise/fall of mercury in a 0.5 mm radius glass capillary. Assume that the surface tension for mer
tekilochka [14]

Answer: 0.01 m

Explanation: The formulae for capillarity rise or fall is given below as

h = (2T×cosθ)/rpg

Where θ = angle mercury made with glass = 50°

T = surface tension = 0.51 N/m

g = acceleration due gravity = 9.8 m/s²

r = radius of tube = 0.5mm = 0.0005m

p = density of mercury.

h = height of rise or fall

From the question, specific gravity of density = 13.3

Where specific gravity = density of mercury/ density of water, where density of water = 1000 kg/m³

Hence density of mercury = 13.3×1000 = 13,300 kg/m³.

By substituting parameters, we have that

h = 2×0.51×cos 50/0.0005×9.8×13,300

h = 0.6556/65.17

h = 0.01 m

8 0
3 years ago
Please help urgent i need help easy queston
mihalych1998 [28]
I believe it’s B but i’m not sure
3 0
3 years ago
A body of mass 3.0Kg is acted upon by a force of 24N, if the frictional force on the body is 13N.Calculate the acceleration of t
lisabon 2012 [21]

Answer:

Fnet=ma

24-13=3a

11/3=a

a=3.6m/s2

4 0
3 years ago
The noise level coming from a pig pen with
sweet [91]

Answer:

The decibel of the remaining pigs is 51.5 dB.

Explanation:

Decibel (dB) is a unit of measure of the intensity of a given sound.

Number of pigs = 199, noise level = 74.3 dB.

Given that the intensity (I) of the sound from the pen is proportional to the number of pigs (N), thus:

                       I    \alpha  N

                       I = kN

where k is the constant of proportionality.

⇒                    k = \frac{I}{N}

                         = \frac{74.3}{199}

                      k = 0.3734

When 61 numbers of pigs were removed, the number of remaining pigs (N) squealing at their original level is 138.

Thus, the becibel level (I) of the remaining pigs can be determined by:

                  I = kN

                    = 0.3734 × 138

                   = 51.53 dB

The becibel level (I) of the remaining pigs is 51.53 dB.

6 0
3 years ago
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