Answer:
The work required to stretch a spring 12 ft beyond its natural length is 432 ft-lb
Explanation:
The work to stretch a spring is calculated using the formula:
Equation (1)
W = work in ft-lb
k = spring constant in lb/ft
x = spring deformation in ft
we clear k from the equation (1)
Equation (2)
We replace x = 2ft, W = 12 ft-lb in the equation (2)
Calculation of work required to stretch spring 12 ft
We replace k = 6 lb/ft and x = 12ft in the equation (1)
Answer: The answer is in the figure attached.
Explanation:
The Work done by a Force refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.
It should be noted that it is a scalar magnitude, and its unit in the <u>International System of Units</u> is the Joule (J). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:
However, in the British Engineering and Gravitational Systems its unit is Foot-pound (ft-lb). Where
Now, when the applied force is constant and the direction of the force and the direction of the movement (traveled distance) are parallel, the equation to calculate it is:
So, taking into account the explanation above, the attached table shows the Work done for each situation.
Answer:
PE=0.29J
Explanation:
According to the description, there is a angle and in point swung upward of 70°
So,
Appling the equation of Potential Energy we have,
Mountains are one of the most affected by weathering.