I don't understand what the question is asking
<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
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Answer:
the percent error is 6.25%
Step-by-step explanation:
The computation of the percent error is shown below:
Percent error is
= (Experimental value - accepted value) ÷ (experimental value) × 100
= (80 degrees - 75 degrees) ÷ (80 degrees) × 100
= (5 degrees) ÷ (80 degrees) × 100
= 0.0625 × 100
= 6.25%
hence, the percent error is 6.25%
We simply applied the above formula so that the correct value could come
And, the same is to be considered
I have another total loan payment formula (see attached):
Total = rate * principal * # of payments / (1-((1 + rate)^-n))
Total = .005 * 15,000 * 60 / (1- ((1.005)^-60)
Total = 4,500 / (1 -0.7413721962)
Total = 4,500 / 0.2586278038
Total = 17,399.52
I know that is NOT one of the answers but I am sure of the formula and the calculations. I hope this helps.