Answer:
True
Step-by-step explanation:
In Prime factorization, we are expected to obtain factors that are prime numbers that can multiply themselves to give the original number. So long as the first factor can divide the number without a remainder, other remaining factors can be multiplied together to give the original number.
Prime factorization of the number, 15 goes thus;
15/3=5
5/5=1
3*5=15
So, all the factors multiply to give the original number.
Hey there!
One way to do this is find all the factors of 6 and then see which pair fit the requirements.
The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)
You can find them by asking if each number can go into 6.
1, 2, 3, and 6 all go into 6, while 4 and 5 do not.
The requirements we have is that they must be consecutive <u>and</u> have a product of 6.
Consecutive means right after one another.
The only numbers that fit this are 2 and 3.
2 x 3 = 6
Hope this helps!
Answer:
(f - g)(x)= - 6 {x}^{2} - 8x + 9
(f - g)(-4!)= - 55
Step-by-step explanation:
