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sineoko [7]
2 years ago
14

Help me I can’t get it right

Mathematics
1 answer:
Ganezh [65]2 years ago
4 0

Answer:

Step-by-step explanation:

Area of rectangle I = length *width = 17 *8 = 136 square meters

Area of rectangle II = 20 * 9 = 180 square meters

Area of square III = 4 * 4 = 16 square meters

Area of the figure = 136 + 180 + 16 = 332 square meters

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What is the area of a regular hexagon with side length of 12.7 and apothem length of 11?
marusya05 [52]

Answer:

I donot know pls for give me

6 0
2 years ago
The line that passes through the point (-4, 2) and has a
xxMikexx [17]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of line

3 0
2 years ago
Determine X and Y<br>(2+i) (x+yi) = -7+3i​
IrinaK [193]

Answer:

x=-11\5+13\5i-iy

y=ix+(13\5+11\5i)

Step-by-step explanation:

x+yi=-7+3i\2+i

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=-11\5+13\5i

x=-11\5+13\5i-yi

x=-11\5+13\5i-iy

x+yi=\frac{-7+3i}{2+i}

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=\frac{-11+13i}{5}

x+yi=-\frac{11}{5}+\frac{13}{5}i

yi=-\frac{11}{5}+\frac{13}{5}i-x

\frac{iy}{i}=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

y=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

7 0
3 years ago
Find the difference 5 1/3 - 3 2/3
Natalija [7]
<span>Find the difference 5 1/3 - 3 2/3

</span>5 \dfrac{1}{3}- 3 \dfrac{2}{3}=   \\ \\   \\  \dfrac{5*3+1}{3}-  \dfrac{3*3+2}{3}=   \\  \\ \\  \dfrac{16}{3}-  \dfrac{11}{3}=  \dfrac{16-11}{3}=    \boxed{ \frac{5}{3}= 1 \frac{2}{3}}  \\  \\<span>
</span>
6 0
3 years ago
6. A chemist wishes to make 5 liters of an 7% acid solution by mixing a 10% acid
larisa [96]

Answer:

The chemist will mix 3 liters of the 5% acid solution and 2 liters of the 10% acid solution to get 5 liters of 7% acid solution

Step-by-step explanation:

Here, we are interested in finding the number of liters of each solution the chemist have to make use;

Let the number of liters of the 5% acid solution be x while the number of liters of the 10% acid solution be y

Mathematically;

x + y = 5 •••••••••(i)

Also, let’s work with the percentages now

( x * 5%) + (y * 10%) = (5 * 7%)

0.05x + 0.1y = 0.35 ••••••••(ii)

From i , x = 5-y

Substitute this into ii

0.05(5 -y) + 0.1y = 0.35

0.25 - 0.05y + 0.1y = 0.35

0.25 + 0.05y = 0.35

0.05y = 0.35 -0.25

0.05y = 0.1

y = 0.1/0.05

y = 2

But x + y = 5

x + 2 = 5

x = 5-2

x = 3

3 0
3 years ago
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