In C, denominator is x-3 and denominator should not be 0 . So we set x-3 to 0 and solve for x, that is
x-3=0
x=3
So domain can't be 3.
And if we see the equation, we will get the numerator and denominator both have same degree. So
Horizontal asymptote= numerator's leading coefficient /denominator's leading coefficient .
y= 2/1 =2
So at y=2, there is a horizontal asymptote , because of which y =2 is not a part of the range .
THerefore the correct option is C .
The required day is Thursday.
Given that;
The 4th day of the month is Tuesday.
We have to find day after three days of 24th
What are odd days in a calendar?
In a given period, the number of days more than the complete weeks are called odd days.
Now,
We know that three days after 24th is 27th.
So, the number of days between 4th and 27th = 23
Since, number of odd days is remainder after dividing 23 by 7
Therefore, odd days = 2
Hence, the day after three days of 24th = Tuesday + 2 days = Thursday
Thus the required day is Thursday.
To learn more about odd days of calendar visit:
brainly.com/question/22080497
#SPJ4
Answer:
10.8 cm
Step-by-step explanation:
we know that
1) A square picture with side length 30 cm is scaled by 60% on a photocopier
Remember that
so
The length of the first copy of the picture is
2) The copy is then scaled by 60% again
so
The length of the second copy of the picture is
4((2)(8)−6)+(8)(3)
=4(16−6)+(8)(3)
=(4)(10)+(8)(3)
=40+(8)(3)
=40+24
=64