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3 years ago

15

in 1950, the population of a city was about 800,000 people. over the next 50 years , the population increased to 1.3 million. fi

nd the percent of increase

1 answer:

nordsb [41]3 years ago

5 0

Subtract 1.3 million from 800,000 and you get ur answer

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Find the mean absolute deviation (MAD) of the data in the pictograph below

mezya [45]

Answer:

16

Step-by-step explanation:

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4 years ago

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Which of these numbers is a prime number: 1, 11, 21, 51?

statuscvo [17]

Answer:

11 and 51

Step-by-step explanation:

1 technically isn't a prime since a prime can only be divided by two things (itself and 1) and 1 can only be divided by 1.

21 can be divided by 1, 3, 7, and 21 so it is not prime.

Hope this helps!

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3 years ago

A parachutist's rate during a free fall reaches 198 feet per second. What is this rate in meters per second? At this rate, how m

amm1812

Answer:

300 feet

Step-by-step explanation:

If we were using feet the expression would be 198x, where x is feet per second

Since they are asking in meters we need to convert feet to meters

When you do that you get 60

Now the expression is 60x

When you plug 5 into the equation it is 300

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3 years ago

36^x-2=6 solve for x

Lina20 [59]

Answer:

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Take logarithm of both sides of the equation to remove the variable from the exponent.

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3 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago