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mafiozo [28]
3 years ago
13

Uggh!! help pls last question

Mathematics
2 answers:
RideAnS [48]3 years ago
8 0

Answer:

The answer is 46.

Step-by-step explanation:

You have to substitute the value of a and c into the expression :

a + 9c

Let a = 10,

Let c = 4,

10 + 9(4)

= 10 + 36

= 46

Mnenie [13.5K]3 years ago
4 0

First, insert the given numbers into the equation. (a = 10 , c = 4)

<em>a + 9c becomes 10 + (9 × 4)</em>

Use PEMDAS  (parenthesis, exponents, multiplication, division, addition, & subtraction) to solve the equation.

First, do the multiplication inside of the parenthesis.

9 × 4 = 36

Now do the addition.

10 + 36 = 46

<h2>Answer:</h2>

<u>10 + (9 × 4) = </u><u>46</u>

hope this helps :)

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Anika [276]

Answer:

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Step-by-step explanation:

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4 years ago
Help help please please
gregori [183]

Answer:

c=√74

Step-by-step explanation:

h=c

p=5

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Using pythogorean theorem,

h^2=p^2+b^2

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c=√(49+25)

c=√74

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3 years ago
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It costs $3.99 for 25 fl. Oz. Of detergent or $6.99 ffor fl. Oz. Which is a better buy
mash [69]

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5 0
3 years ago
Is there any video related to this or can you explain how to do it
uranmaximum [27]

Angles ECD  and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

CD || EF

Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

4 0
3 years ago
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N76 [4]

Answer:

Angle C =  45°

Step-by-step explanation:

Hello There!

If you didn't know opposite angles are congruent in parallelograms

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4 0
3 years ago
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