Complete question :
A traditional "square" bale of hay is actually in the shape of a rectangular prism. Its dimensions are 2 feet by 2 feet by 4 feet. How many square bales contain the same amount of hay as one large "round" bale of height is 4 ft and its width is 5 ft?
Answer:
4 bales
Step-by-step explanation:
Given :
Dimension of rectangular prism = 2 feet by 2 feet by 4 feet
Round Bale:
Height = 4 feets
Width = 5 feets
Volume of 'Square' Bale
Volume = 2 feets * 2 feets * 4 feets
Volume = 16ft³
Volume of 'round' Bale
V = πr²h
radius, r = 4/2 = 2 feet ;
V = π * 2^2 * 5
V = 62.831853 ft³
Volume of 'round' bale ÷ Volume of 'square' bale
62.831853 ft³ ÷ 16 ft³
= 3.9269908
= 4 (nearest whole number)
The next number in the pattern would be 14.03.
To find this, note the differences found by subtracting each number from the number that comes after.
4.03 - 2.78 = 1.25
5.78 - 4.03 = 1.75
8.03 - 5.78 = 2.25
10.78 - 8.03 = 2.75
Since each difference goes up by .5 each time, we know we can add .5 to the last difference to find the newest one.
2.75 + .5 = 3.25
Now we have the difference, so we add that to the last number.
10.78 + 3.25 = 14.03
Answer:
The third answer choice (x = 2) is the correct one.
Step-by-step explanation:
2 ln 4x = 2 ln 8 simplifies to ln 4x = ln 8.
Next, ln 4x = ln 8 simplifies to 4x = 8, and, finally,
we get
x = 8/4 = 2.
The third answer choice (x = 2) is the correct one.
Okay well then no b the answer is b no