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babymother [125]
3 years ago
12

A/An _____ is a material in which charges will not move easily, whereas a/an _____ is a material that allows charges to move abo

ut easily. Question 6 options: conductor, insulator insulator, conductor electroscope, conductor insulator, electroscope
Physics
1 answer:
Svet_ta [14]3 years ago
3 0

Insulator and conductor

Explanation:

An insulator is a material in which charges will not move easily whereas a conductor is one in which charges move about easily.

  • Insulators do not have free mobile electrons or ions that allows for the passage of electric current.
  • Most plastics, woods e.t.c are insulators.
  • Conductors allow electric current to pass through the presence of free mobile electrons.
  • Most conductors are metals and ionic compounds in aqueous solutions.

Learn more:

Conductors brainly.com/question/8913793

#learnwithBrainly

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In the equation 234Th90 -> 234Pa91 + X, which particle is represented by X?
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This process shows alpha decay so X represents an alpha particle. The characteristic of alpha decay is that the mass number stays constant while the proton number increases.
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Both Josef Loschmidt and Amedeo Avogadro contributed to our understanding of basic molecular numbers, sizes, and reaction ratios
lbvjy [14]

The  Avogadro’s number is used to represent the number of elementary entities that exist in one mole of a compound.

<h3>What is the  Avogadro’s number?</h3>

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5 0
2 years ago
An airplane traveling at half the speed of sound emits a sound of frequency 4.68 kHz. (a) At what frequency does a stationary li
kkurt [141]

Answer:

(a) 9.36 kHz

(b) 3.12 kHz

Explanation:

(a)

V = speed of sound

v = speed of airplane = (0.5) V

f = actual frequency of sound emitted by airplane = 4.68 kHz = 4680 Hz

f' = Frequency heard by the stationary listener

Using Doppler's effect

f' = \frac{Vf}{V-v}

f' = \frac{V(4680)}{V-(0.5)V)}

f' = 9360 Hz

f' = 9.36 kHz

(b)

V = speed of sound

v = speed of airplane = (0.5) V

f = actual frequency of sound emitted by airplane = 4.68 kHz = 4680 Hz

f' = Frequency heard by the stationary listener

Using Doppler's effect

f' = \frac{Vf}{V+v}

f' = \frac{V(4680)}{V+(0.5)V)}

f' = 3120 Hz

f' = 3.12 kHz

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