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4 years ago

Hi

Physics

2 answers:

TEA [102]4 years ago

8 0

Answer:

Because they memorized the keys

Or their just used to using a keyboard

Explanation:

valkas [14]4 years ago

5 0

I try to aim a the right key or do typing lessons

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One kg of air is contained in a piston-cylinder system and it undergoes a Carnot cycle having an efficiency of 60%.The heat tran

wlad13 [49]

Answer is in the file below

tinyurl.com/wtjfavyw

4 0

3 years ago

Help plz anyone ?????

Alexus [3.1K]

Answer:

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3 years ago

What is the gpe of a 200 kg hot air ballon 21,000 m above the ground?

stiv31 [10]

gravitational Potential energy is given by

$GPE = mgh$

here we have

m = 200 kg

h = 21000 m

now we will have

$GPE = 200(9.8)(21000)$

$GPE = 4.116 \times 10^7 J$

so GPE of balloon will be 41160000 J above the given height from ground

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3 years ago

Activity

qwelly [4]

Answer:Eating. Your muscles in your arms and mouth use energy to feed itself. Then your body digest the food which also takes energy.

Sleep. When your tired, you don’t have much energy. It is said that you use more energy while your sleeping. But how do you become energized if you were using even more energy than before?

6 0

3 years ago

A photon of red light (wavelength = 710 nm) and a ping-pong ball (mass = 2. 40 × 10^-3 kg) have the same momentum. At what speed

Paha777 [63]

The speed of the ball moving is

$v = 3.94 \times 10 {}^{ - 25}m/s$

what is momentum?

The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.

For photons with wavelength λ,this equation does not hold.Instead, the momentum of the Photon is given by p Photon = h/λ

where,h is the planck's constant.

The momentum of the red Photon is

given:

$h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)$

$λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)$

$p \: photons = \frac{6.626 \times 10 {}^{ - 34}kgm {} ^{2}/s }{700 \times 10 {}^{ - 9}m }$

$= 9.47 \times 10 {}^{ - 28}kgm /s$

since,the Photon and the ping-pong ball have the same momentum,we have

$pball = pphotons = \frac{6.626 \times 10 {}^{ - 34}kgm/s }{700 \times 10 {}^{ - 9} }$

$pball = mv,m = 2.40 \times 10 {}^{ - 3}kg$

$v = 3.94 \times 10 {}^{ - 25} m/s$

Therefore, if the red photon and the ping-pong ball have the same momentum, the ping-pong ball must have a speed of approximately

$v = 3.94 \times 10 {}^{ - 25}m/s$

learn more about momentum of photon from here: brainly.com/question/28197406

#SPJ4

3 0

2 years ago