Question

At the lowest point in a vertical dive (radius = 0.58 km), an airplane has a speed of 300 km/h which is not changing. Determine the magnitude of the acceleration of the pilot at this lowest point. Group of answer choices

Answer 1

Answer:

The centripetal acceleration is $a = 11.97 \ m/s^2$

Explanation:

From the question we are told that

     The radius  is $r = 0.58 \ km = 0.58 * 1000 = 580 \ m$

      The speed is $v = 300\ km /hr = \frac{300 *1000}{1 * 3600 } = 83.33 \ m/s$

The centripetal acceleration of the pilot is mathematically represented as

       $a = \frac{v^2 }{r}$

substituting  values

      $a = \frac{(83.33)^2 }{580}$

     $a = 11.97 \ m/s^2$