Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
= 37.5 m/s
velocity initial = 35 km/hr x 1hr /3600 s x 1000 m/1 km
= 9.72 m/s
a) acceleration = 2.646 m/s^2
b) acceleration in g units = (2.646m/s^2)/(9.8m/s^2)
= 0.27 units
Answer : The weight of the car is 9800 N
Explanation :
It is given that,
The mass of the car, m = 1000 kg
We have to find the weight of the car. The weight of an object is defined as the force acting on it under the action of gravity. The mass of an object is the amount of matter present in it.
Using second law of motion :
W = m g
Where
m is the mass of the car
g is the acceleration due to gravity g = 9.8 N/kg
W = 1000 kg × 9.8 N/kg
W = 9800 N
So, the weight of the car is 9800 N.
Hence, this is the required solution.
Its called electro motive force . let me know if its right
Explanation:
Fe₂O₃ + CO → Fe₃O₄ + CO₂
Balancing the equation above, we can derive simple mathematical equations that are very easy to solve.
aFe₂O₃ + bCO → cFe₃O₄ + dCO₂
a,b,c and d are the coefficients needed to balance the equation above;
Conserving Fe; 2a = 3c
O: 3a + b = 4c + 2d
C: b = d
let a = 1;
c = 
Since b = d
3a + d = 4c + 2d
3a = 4c + 2d - d
3a = 4c + d
a = 1, c = 
3 = 4 x
+ d
d = 
b = 
multiplying a, b, c and d by 3:
a = 3 b = 1 c = 2 and d = 1
3Fe₂O₃ + CO → 2Fe₃O₄ + CO₂
Learn more:
Balanced equation brainly.com/question/2612756
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