Answer:
length=53 in
width= 23 in
Step-by-step explanation:
First, we know that each corner has now a square of 6 in long, so the heigth of the box will be of this size (as you can see in the picture attached). Then, the length and the width of the box would be the same as the piece, but with 12 in less. Therefore the equations to solve the problem are:

We factorize the 6 and we get:

Finally we solve for x, and we get the initial dimensions of the piece of metal:


Answer:
(3 and 15)
Step-by-step explanation:
If the product of both of these two numbers needs to be a negative 45 then there are no pair of integers that comply with both requirements.
If the multiplication in the question is wrong and it is a positive 45 then the pair of integers that would comply with these requirements would be (3 and 15). Multiplying this pair together would give you 45 and the difference between them is also 12 meaning it complies with both requirements that were asked for in the question.
The number is 79 that is prime
Answer:
61
Step-by-step explanation:
Please give me brainliest :)