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3 years ago

The length of a rectangle is 3 inches more than its width. If the perimeter is 42 inches, find the dimensions of the rectangle.

Mathematics

2 answers:

mojhsa [17]3 years ago

5 0

The problem uses the perimeter formula. P = 2w + 2l where w is the width, and l is the length.

We know the length (l) is 3 inches longer than it's width (or l = w+3). Substitute w +3 into Perimeter equation

P = 2w + 2(w+3). That simplifies to P = 4w + 6.

Since P + 42, we have 42 = 4w +6. With some simple algebra we find that w = 9 and l = 12.

Hope this helps!

eimsori [14]3 years ago

3 0

Width is 12 and length is 9

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Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

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Answer :

no. of solutions for the eqn 10626

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