The length of a rectangle is 3 inches more than its width. If the perimeter is 42 inches, find the dimensions of the rectangle.
2 answers:
The problem uses the perimeter formula. P = 2w + 2l where w is the width, and l is the length.
We know the length (l) is 3 inches longer than it's width (or l = w+3). Substitute w +3 into Perimeter equation
P = 2w + 2(w+3). That simplifies to P = 4w + 6.
Since P + 42, we have 42 = 4w +6. With some simple algebra we find that w = 9 and l = 12.
Hope this helps!
Width is 12 and length is 9
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