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oksian1 [2.3K]
3 years ago
8

Suppose you had x dollars in your bank account. You spent $22 but have at least $28 left. How much money did you have initially?

Write and solve an inequality that represents this situation.
A) x + 22 ≤ 28 ; x ≤ 72

B) x - 22 ≥ 28 ; x ≥ 50

C) x - 22 > 28 ; x > 50

D) x + 22 ≥ 28 ; x ≥ 72
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0

Answer:

B

Step-by-step explanation:

spent 22 ---> x - 22.

at least 28 left ---> (x - 22) >= 28

SOLVE:

x - 22 >= 28

x >= 50

Natasha2012 [34]3 years ago
6 0

Answer:

B) x - 22 ≥ 28 ; x ≥ 50

Step-by-step explanation:

Given,

The original amount in the bank = x dollars,

After spending $ 22,

Remaining amount = ( x - 22 ) dollars,

∵ Remaining amount must be at least $ 28,

⇒ x - 22 ≥ 28

Which is the required inequality,

Add 22 both sides,

x -22 + 22 ≥ 28 + 22

x ≥ 50

Hence, option B is correct.

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It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
Please help me find g(10).
timama [110]

Answer:

Step-by-step explanation:

g(10) = (10^2-8)/(10+4)= (100 - 8)/14 = 92/14 = 48/7 or 6 6/7

7 0
3 years ago
30 points
igomit [66]
Since the rate of descent is a constant this is a linear equation and can be expressed as:

h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)

h=-2t+b, using the point (3,67) we can solve for b, or the initial height

67=-2(3)+b

67=-6+b

73=b  so the initial height was 73 ft and the height equation is then:

h(t)=67-2t so when t=8 you have:

h(8)=67-2(8)

h(8)=67-16

h(8)=51 ft
8 0
3 years ago
Solve mathematics problem in photo please!
laila [671]
Hello,

8/(x-7)=7/2
==>(x-7)*7=8*2
==>7x-49=16
==>7x=65
==> x =9+2/7

Answser A
8 0
3 years ago
A crate that is 10 inches long, 8 inches wide, and 3 inches high is shown above. The floor and the four walls are all one inch t
miskamm [114]

Answer:

48

Step-by-step explanation:

The exterior of the crate is 10 inches long, meaning that the inside measurement is 8 inches.  Next, the 8 inch width corresponds to 6 inches inside.  Finally, the 3 inch height corresponds to 1 inch interior height.

Thus the inside floor of the box is 8 by 6 inches, or 48 square inches.

Since the inside height is only 1 inch, this means that 48 one-inch cubical blocks will fit inside the crate.

7 0
3 years ago
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