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swat32
3 years ago
14

What does the C equal to in -1/6 +7/6 = c

Mathematics
1 answer:
STALIN [3.7K]3 years ago
6 0

Answer:

c = 1

Step-by-step explanation:

we have -1/6 + 7/6

since 6 is a common denominator we can do

\frac{-1}{6} +\frac{7}{6} = c\\\frac{-1+7}{6} = c\\\frac{6}{6} = c\\1 = c\\c = 1

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Using the table find the value of y when x=2<br>​
Tju [1.3M]

Answer:

y = 8 when x = 2

Step-by-step explanation:

y = 4x

6 0
3 years ago
The cone below has a radius of 3 inches, a height of 4 inches, and a slant height of 5 inches. What is the approximate lateral a
Natali [406]
<span>Cone Lateral Area = (<span>π<span> • r •<span> slant height)
</span></span></span></span><span>Cone Lateral Area = (PI * 3 * 5)
</span>Cone Lateral Area = <span> <span> <span> 47.1 </span> </span> </span> square inches
Cone Lateral Area = <span> <span> 47</span></span> square inches (rounded to nearest whole number).


6 0
3 years ago
Read 2 more answers
If 5 a solution of 3x + 30 = 9x?
const2013 [10]

Answer:

x = 5

Step-by-step explanation:

This equation can be rearranged in order to easily solve.

First, rearrange the equation by simply flipping it.

3x + 30 = 9x → 9x = 3x + 30

Then, you may solve for x.

9x = 3x + 30 subtract 3x from both sides of the equation

6x = 30 divide by 6 on both sides of the equation

x = 5

8 0
3 years ago
Find the equilibrium quantity and equilibrium price for the commodity whose supply and demand functions are given.
expeople1 [14]
Rewriting the two equations:

[Supply] p = q^2+20
[Demand] p=-4q^2+10q+18600

Equilibrium price is when 
Supply = Demand
q^2+20 = -4q^2+10q+18600
q^2+4q^2+20-10q-18600 = 0
5q^2-10q-18580=0 ⇒ Simplifying the equation by dividing each term by 5

q^2-2q-3716=0

The simplified equation is in quadratic form.
There are three main methods for solving a quadratic equation: factorizing, completing the square, or quadratic formula. 

Using the formula, we need the value of a, b, and c which is the constant of the quadratic equation. 
q_1= \frac{-b+ \sqrt{(b)^2-4ac)} }{2a}, and q_2= \frac{-b- \sqrt{(b)^2-4ac)} }{2a}


We have a = 1, b = -2, and c = -3716
Substituting these values into the formula we have
q_1= \frac{-(-2)+ \sqrt{(-2)^2-4(1*-3716)} }{2} =61.97
q_2= \frac{-(-2)- \sqrt{(-2)^2-4(1*-3716)} }{2} =-59.97

Since 'q' represents a quantity, we can't have negative values, so we choose the value of 'q' to be 61.97 ≈ 62 (rounded to the nearest whole number)

Answer: Equilibrium quantity = 62
4 0
3 years ago
Did I do this right?
kupik [55]

Answer:

Yes, you did.

Step-by-step explanation:

5 0
3 years ago
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