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Mariana [72]
3 years ago
6

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 9 m

inutes. Find the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes.
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

P(greater than 1.25 minutes) = 0.8611 (Approx)

Step-by-step explanation:

Given:

Waiting time = 0 - 9 minutes

Find:

Probability that selected passenger has a waiting time greater than 1.25 minutes.

Computation:

⇒ The probability that a randomly selected passenger has a waiting time greater than 1.25 minutes =

⇒  P(greater than 1.25 minutes) = [9-1.25] / 9

⇒ P(greater than 1.25 minutes) = [7.75] / 9

⇒ P(greater than 1.25 minutes) = 0.8611 (Approx)

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5(12 + m) = 100 find m
Llana [10]

Answer:

8

Step-by-step explanation:

1. multiply 5 and 12 to get 60

2. multiply 5 and m to get 5m

3. the equation would be 60 + 5m = 100

4. next, subtract 60 on both sides

5. your equation so far is 5m = 40

6. then divide 5 on both sides

7. then you have your answer m = 8

3 0
3 years ago
In which of the expressions below will x = 12.5? Select all
erma4kov [3.2K]

The answer is D

2x / 5 = 5

5 x 5 = 25

2x = 25

25/2

x= 12.5

4 0
3 years ago
Read 2 more answers
Please answer quickly
katrin2010 [14]

Have no clue


Step-by-step explanation:


3 0
3 years ago
Show work. Find the mean and standard deviation of the data. Round to the nearest tenth. 20,16,18,14,9,20,16
postnew [5]
20+16+18+14+9+20+16=113
113÷7=16.14285714
after rounded the answer would be 16.
hope that's correct.
6 0
3 years ago
What two numbers' sum=-4 and product=-2
n200080 [17]

Let <em>a</em> and <em>b</em> be the two numbers. Then

<em>a</em> + <em>b</em> = -4

<em>a b</em> = -2

Solve the second equation for <em>b</em> :

<em>b</em> = -2/<em>a</em>

Substitute this into the first equation:

<em>a</em> - 2/<em>a</em> = -4

Multiply both sides by <em>a</em> :

<em>a</em>² - 2 = -4<em>a</em>

Move 4<em>a</em> to the left side:

<em>a</em>² + 4<em>a</em> - 2 = 0

Use the quadratic formula to solve for <em>a</em> :

<em>a</em> = (-4 ± √(4² - 4(-2))) / 2

<em>a</em> = -2 ± √6

If <em>a</em> = -2 + √6, then

-2 + √6 + <em>b</em> = -4

<em>b</em> = -2 - √6

In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.

7 0
3 years ago
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