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3 years ago

What is an equation of the line that passes through the points (-4, -1) and (2, 8)?

Mathematics

1 answer:

aev [14]3 years ago

6 0

Answer:

Gggyu

Step-by-step explanation:

Hbyuk

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What is the answer for N-6/3=4

konstantin123 [22]

N=6 Is the answer to your question

4 0

4 years ago

an old book listed that $72$ turkeys were bought for $\$\square.\square\square$ each, at a total cost of $\$\square 67.9\square.

Westkost [7]

The cost of each turkey, if each is a smudge that represents some unreadable digit is $0.94

<h3>Cost of each turkey</h3><h3 />

Total number of turkey bought = 72
Total cost = $67.9

Cost of each turkey = Total cost / Total number of turkey bought

= 67.9 / 72

= 0.943055555555555

Approximately,

Cost of each turkey = $0.94

Therefore, the cost of each turkey, if each is a smudge that represents some unreadable digit is $0.94

Learn more about unit rate:

brainly.com/question/4895463

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4 0

2 years ago

PLEASE HELP!!<br> Convert each linear equation to standard form.<br> y-4= -2(x+3)

hjlf

So first, this is point slope form. The first step is to distribute.)
$y-4=-2x-6$
Then add 4 to both sides.
$y=-2x-2$
Then add 2x and it becomes
$2x+y=-2$

4 0

4 years ago

Read 2 more answers

Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter

jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

$\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\$

since s(t) is the arc length for r(t), which is define as

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt$

if we substitute the value of r'(t) we arrive at

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\$

$s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }$

substituting the value of t in to the given vector equation we have

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

4 0

4 years ago

Two of the angles are listed. Find the measure of the third angle in each triangle.

torisob [31]

Attached the solution and work. The x,y,n are just variables I put in so you could see how I solved for the missing angle.

3 0

3 years ago