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Yuliya22 [10]
2 years ago
12

What is the area of a triangle with a base of 55 cm and a height of 78 cm?

Mathematics
2 answers:
Fittoniya [83]2 years ago
4 0

Answer:

2145 cm2

Step-by-step explanation:

yKpoI14uk [10]2 years ago
4 0

Answer:

2145

Step-by-step explanation:

To find the area of a triangle you use the equation Height x Base divided by 2

so you would do 55 multiplied by 78 which would get you 4290

then you would divide  it by 2 to get 2145

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There are exactly triangles when two sides measure 6 inches and the angles included by these two sides measure 90 degrees
Alla [95]

Answer:

Ok

Step-by-step explanation:

3 0
2 years ago
Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr
drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

AC^2= AB^2+BC^2

\Rightarrow (x+3)^2=x^2+8^2

\Rightarrow x^2+6x+9=x^2+64

\Rightarrow 6x=64-9=55

\Rightarrow x=55/6=9.17 chi.

Hence, the height of the pole, AB=x=9.17 chi,

and the length of the rope, x+3=9.17+3=12.17 chi.

8 0
3 years ago
1. Find the value of (−0.024)square
Lelu [443]
0.000576 is the right awnser
4 0
3 years ago
What is 10.5% commission of $85,000
VikaD [51]
<span>What is 10.5% commission of $85,000

85,000 x 0.105 = 8,925

answer
$8,925 is </span>10.5% commission of $85,000
8 0
3 years ago
Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same ti
Mariulka [41]

Let time be x distance be y

  • 140x=y-(1)
  • 290x=360-y-(2)

Put value in eq(2)

\\ \rm\longmapsto 290x=360-(140y)

\\ \rm\longmapsto 440x=360

\\ \rm\longmapsto x=1.2min

Put it in eq(1)

  • d=1.2(140)=168m
7 0
2 years ago
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