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Alina [70]
3 years ago
15

The measure of an angle is two times the measure of its complementary angle. What is the measure of each angle?

Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

Step-by-step explanation:

2x = 90

x = 45

45 and 45

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Special right triangles
blondinia [14]
In the question you provided above what do you mean can you please give more details.


7 0
3 years ago
Read 2 more answers
What is 400 percent as a mixed number?
prohojiy [21]
You can put 400/100 to get the fraction 4/1 or 4, it is not a mixed number though. So the final answer is 4
8 0
2 years ago
Equation of the line that passes through (7,-1) and (-3,-1)
Archy [21]

Answer:

y = - 1

Step-by-step explanation:

Note the y- coordinates of both points are equal, both - 1

This indicates the line is horizontal and parallel to the x- axis with equation

y = c

where c is the value of the y- coordinates the line passes through

The line passes through (7, - 1 ) and (- 3, - 1 ) with y- coordinates - 1 , then

y = - 1 ← equation of line

6 0
2 years ago
Please help quickly <br><br> AB=AD and BC=DC<br> x=?
Arisa [49]

Answer:

x = 110

Step-by-step explanation:

measure of abd is 35, meaning adb is also 35.

so dab + abd + adb is 180

=> x + 35 + 35 = 180

=> x + 70 = 180

=> x = 180-70

=> x = 110

110 degrees is the value of x.  

8 0
1 year ago
Each container must hold exactly 1 litre of water Each container must have a minimum surface area
Arada [10]

The containers must be spheres of radius = 6.2cm

<h3>How to minimize the surface area for the containers?</h3>

We know that the shape that minimizes the area for a fixed volume is the sphere.

Here, we want to get spheres of a volume of 1 liter. Where:

1 L = 1000 cm³

And remember that the volume of a sphere of radius R is:

V = \frac{4}{3}*3.14*R^3

Then we must solve:

V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{  (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm

The containers must be spheres of radius = 6.2cm

If you want to learn more about volume:

brainly.com/question/1972490

#SPJ1

6 0
2 years ago
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