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NikAS [45]
3 years ago
14

Given f(x) = 1/4 (5-x)^2 what is the value of f(11)

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

9

Step-by-step explanation:

f(11) means that x = 11 (plug it in)

f(11) = 1/4(5-11)^2

      = 9

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nikklg [1K]
We have to find the period of the parent cosine function and the period of the function showed on the graph.
Period = 2π / B, where B is the coefficient of x - term.
1. For the function: y = cos x,  B = 1
Period = 2 π / 1 = 2 π = 360°.
2. For the graphed function ( from the picture ):
Period = 6 π = 1,080°
4 0
3 years ago
Read 2 more answers
Evaluate the function h(x)=18-x when x=-6
IRINA_888 [86]
You just plug in the given value of x into the function equation. H(x)=18-(-6) which breaks down to 18+6. So the answer is 24.
5 0
4 years ago
Find the measure of the indicated side
Archy [21]
The correct answer is 12

The triangle above is an equilateral triangle which means all sides will have the same value as each other and since you were given the value of one side (12), all other sides will be 12
6 0
3 years ago
Find the vertical asymptote(s) of f of x equals quantity 4 x squared plus 3x plus 6 end quantity over quantity x squared minus 3
siniylev [52]

The vertical asympototes of f(x) are  at x = -6 and x = 6

Step-by-step explanation:

To find the vertical asymptote(s) of a rational function,

  • Equate the denominator by 0
  • Solve it for x
  • If x = a, then the vertical asymptote is at x = a

∵ f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}

- Equate the denominator x² - 36 by 0

∵ x² - 36 = 0

- Add 36 to both sides

∴ x² = 36

- Take √ for both sides

∴ x = ± 6

∴ There are vertical asymptotes at x = -6 and x = 6

The vertical asympototes of f(x) are  at x = -6 and x = 6

Learn more:

You can learn more about the asymptotes in brainly.com/question/6459599

#LearnwithBrainly

4 0
3 years ago
Mrs. Wheeler prepares a list of 434343 US presidents, 313131 of whom served in the military. Then 888 students each select a pre
grigory [225]

Answer:

Probability of atleast one of the students(888) selecting a president with no service in the military reaches 1.

Step-by-step explanation:

Total Presidents in list = 434343

Military men to be president = 313131

Probability of selecting President who were also military men =

p = 313131/434343 = 0.72

Probability of selecting President who were not military men =

q = 1 - p = 1 - 0.72 = 0.28

Now; no of students who make a choice = 888

no. of Choices made resulting in success = x : {0, 1, 2, 3,............., 888 }

GIVEN CASE:

P(f) = Probability of atleast one student selecting a president with no service in military

This case fails when no one selects a president with no service in military, let us call it P(f').

P(f) = 1-P(f')

Calculating P(f'):

Let us define:

Failure = selecting a president with service in military , p = 0.72

Success = selecting a president with no service in military , q = 0.28

Using Binomial Theorem:

we have this case when n students make selections and x of them are successful.

P(x) = nCx * q^{x}  * p^{n-x}

In case of f' , n = 888 and x = 0

P(0) = 888 C 0 * (0.28)^{0}  * 0.72^{888-0}

= (888!/(888-0)!) * (1) * (0.72)^{888}\\= (0.72)^{888}\\= 2.047655e-127\\

Hence, P(f') = 2.047655e-127 (reaches 0)

Now: P(f) = 1 - P(f')

P(f) = 1 - 2.047655e-127 = 1

Hence Probability of atleast one of the students(888) selecting a president with no service in the military is 1.

7 0
3 years ago
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